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A sample of gas has an initial volume of 31.4 at a pressure of 1.3 If the sample is compressed to a volume of 15.0 what will its pressure be Assume constant temperature?
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∙ 12y ago
For this you would use Boyle's Law, P1V1 = P2V2. The first pressure and volume variables are before the change, while the second set are after the change. In this case, the volume is being changed and the pressure has to be solved for.
P1 = 1.30 ATM
V1 = 31.4 L
P2 = Unknown
V2 = 15.0 L
P1V1 = P2V2
1.30(31.4)=15.0P
P= 2.72 ATM
Looking at the question simply, you can get an estimate on the pressure because you can see that pressure and volume vary indirectly (if volume goes up, pressure goes down). If the volume is cut in half (roughly), then the pressure should increase by half.
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∙ 12y ago
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A 10.0L balloon is filled with He gas at a pressure of 655mm Hg What is it's new pressure assuming no change in temperature if the volume of He is changed to 1.5L?
You can use the Ideal Gas law which says that for an ideal gas the pressure times the volume divided by the temperature must be a constant number. And in this case since you are given that the temperature is a constant number then the gas law becomes "the pressue times the volume is a constant number". This means whatever their product is at one time , it will equal their product at a different time. The equation would be: Pf x Vf = Pi x Vi where the i & f mean initial & final. You solve this for the unknown final pressure ,Pf as: Pf = ( Pi x Vi )/Vf = ( 655 x 10 )/1.5 = 4367 mm of Hg
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The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
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This cannot be answered without an initial volume or pressure. But the final pressure of an expansion of a gas can be determined by the following formula. PV/T = P'V'/T' where P = pressure absolute V = volume T = temperature absolute ( ' ) indicates the new pressure, volume and temperature because the temperature is constant this can be reduced to PV = P'V' or P' = PV/V'
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If a gas occupies 3.67L at a pressure of 102.5 kPa what will its volume be at 100.9 Kpa at constant temperature?
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If temperature of a gas tripled what happens to the volume?
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