For any lamp to operate at its rated power, it must be subject to its rated voltage. If you connect, say, three identical 120-V rated lamps across a 120-V supply, then each lamp will be subject to one-third of its rated voltage. As a result each lamp will not be able to achieve its rated power. If the lamps have different power ratings, then it is rather more complicated, with the most powerful lamp becoming the dimmest while the least powerful lamp becoming the brightest.
The total voltage in a series circuit does not change when you add bulbs to the circuit. (Assuming a proper low impedance voltage source.) The voltage drop across each bulb, however, decreases as you increase the number of bulbs.
The circuit voltage or the resistance of the individual bulb is needed to answer this question. Divide the total power (400 W) by the supply voltage.
The bulb is dim.Because,the voltage is drops in series connection so you add more bulbs in series the last bulb got low voltage that reason for the bulb is dim
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
If the bulbs are wired in series, the voltage rating for each bulb is the source voltage divided by the number of bulbs in the series. You can tell if they're wired in series by removing a bulb. If all of the other lights go out, you have a series circuit. If all of the other bulbs stay lit, you have a parallel circuit. If half of the lights go out and the other half stay lit, you have two series circuits in parallel. The source voltage is about 110 volts in North America or about 220 volts in Europe (I don't know about Asia or Australia). If you have a series/ parallel mix, count only the bulbs that go out with the one you removed. For example, if you have 50 lights in one series in North America, the voltage across each bulb is about 2.2 volts.
Kirchhoff's Current Law: The sum of the signed currents entering a node is zero. A consequence of this is that, in a series circuit every node only has two connections, one entering and one leaving, thus, in a series circuit, the current is the same at every point. Kirchhoff's Voltage Law: The sum of the signed voltage rises going around a series circuit is zero. This means, for example, that if you have two voltage drops, such as two bulbs in series with a battery, the voltage drops across them will add up to the voltage across the battery.
Nothing.
The total voltage should not change in this case.
In a series circuit, all bulbs are necessary to complete the circuit. If one bulb goes out, the circuit is broken, so none of the bulbs would light up.
Voltage remains constant; current increases.
The circuit voltage or the resistance of the individual bulb is needed to answer this question. Divide the total power (400 W) by the supply voltage.
The bulb is dim.Because,the voltage is drops in series connection so you add more bulbs in series the last bulb got low voltage that reason for the bulb is dim
A: If put in series current will decrease if put in parallel current will increase assuming the input voltage remains the same
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
They don't unless you speaking about a parallel circuit in which total currect would be the sum of all the currents in each light bulb (The more light bulbs, the more current draw) If you're talking about a series circuit, nothing at all happens to the current, as in a seires circuit current is constant throughout the entire circuit (voltage changes). In a case such as this the more light bulbs in the circuit, the less the voltage becomes across those bulbs (furthest from the source), thus they will become dimmer due to lower power (P=IE).
current in series always stays the same
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
If you unscrewed any bulb in the circuit it would turn all of the bulbs off.