4K2Cr2O7 → 4K2CrO4 + 2Cr2O3 + 3O2
k2cr2o7 converts the glycerol to co2 and h2o
potassium dichromate
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
Weigh 4.9035g K2Cr2O7 make up to 1 liter
k2cr2o7 converts the glycerol to co2 and h2o
potassium dichromate
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
1N of k2cr2o7=49.09 gm/1 L 0.25N=12.2725 gm of k2cr2o7 in 1 L of water.
The chemical formula of potassium dichromate is K2Cr2O7
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
When matter is heated it will expand
Weigh 4.9035g K2Cr2O7 make up to 1 liter
No, It's totally different. 1M of K2Cr2O7 is 294.19g/water 1L on the other hands, 1N of K2Cr2O7 is 49.04 g/ water 1L
When solids are heated they turn into liquid
no answer
Aldehydes is the product name of ovi dation of ethanol with k2Cr2O7.