1N of k2cr2o7=49.09 gm/1 L
0.25N=12.2725 gm of k2cr2o7 in 1 L of water.
The chemical formula of potassium dichromate is K2Cr2O7
The titer volume of the sample gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the solution. Similarly, the titer volume for the blank (distilled water) gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the blank. The equation for the titration can be expressed as: Cr2O72 -- + FeSO4 (NH4)2SO4 = Cr+ + NH4+ + Fe 3+ From above equation it can be seen that one molecule of dichromate corresponds to one molecule of Mohr's salt. Thus, the difference in volume of excess K2Cr2O7 reacting with Mohr's solution can be calculated from the expression: = (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) solution - (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) blank = (Vol. of K2Cr2O7 used for oxidation) blank - Vol. of K2Cr2O7 used for oxidation) solution Hence, the difference in the titer volume for the solution and the blank is used to find out the Chemical Oxygen Demand directly.
The chemical forrmula of potassium heptaoxodichromate(VI) is K2Cr2O7. The systematic IUPAC name is potassium dichromate (VI).
The reaction between potassium dichromate (K2Cr2O7) and iron(II) sulfate (FeSO4) results in a double displacement reaction producing iron(III) chromate (Fe2(CrO4)3) and potassium sulfate (K2SO4). The balanced equation is: 3FeSO4 + K2Cr2O7 → Fe2(CrO4)3 + K2SO4.
A solute and solvent make up a solution. The solute is the substance that is dissolved in the solvent to form the solution. The solvent is the substance in which the solute is dissolved.
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
The molarity is 0.001255. Should you really be asking an AP Chem question on Wiki Answers, anyways?
No, molarity and normality are not the same in K2Cr2O7. Molarity is the concentration of a solution expressed in moles of solute per liter of solution, while normality is a measure of concentration based on the equivalents of a solute in a solution. In the case of K2Cr2O7, as it has more than one ion that can undergo reaction, the normality would be different from the molarity.
To prepare a 0.1 N solution of K2Cr2O7, you need to calculate the molar mass of K2Cr2O7 and use the formula for normality. By dividing the given weight by the molar mass, you can determine the number of moles present, and then calculate the normality using the volume of the solution.
Dissolve 294,185 g of potassium dichromate in 1L demineralized water.
To find the volume of 0.1125 M K2Cr2O7 required, first balance the equation: 14H+ + 6Na2SO3 + K2Cr2O7 → 2Cr3+ + 3SO42- + 6Na+ + 2K+ + 7H2O. Then, use the mole ratio to calculate moles of Na2SO3 used, and finally the volume of K2Cr2O7 needed.
K2Cr2O7(aq) ------> 2K+(aq)+Cr2O72-(aq)
The chemical formula of potassium dichromate is K2Cr2O7
Potassium dichromate contain potassium, chromium and oxygen.
The titer volume of the sample gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the solution. Similarly, the titer volume for the blank (distilled water) gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the blank. The equation for the titration can be expressed as: Cr2O72 -- + FeSO4 (NH4)2SO4 = Cr+ + NH4+ + Fe 3+ From above equation it can be seen that one molecule of dichromate corresponds to one molecule of Mohr's salt. Thus, the difference in volume of excess K2Cr2O7 reacting with Mohr's solution can be calculated from the expression: = (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) solution - (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) blank = (Vol. of K2Cr2O7 used for oxidation) blank - Vol. of K2Cr2O7 used for oxidation) solution Hence, the difference in the titer volume for the solution and the blank is used to find out the Chemical Oxygen Demand directly.
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
Aldehydes is the product name of ovi dation of ethanol with k2Cr2O7.