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How much solid potassium dichromate must be added to prepare 150 mL of 0.200 M solution of K2Cr2O7 (molar mass 294 gmol)?
To prepare a 150 mL (0.150 L) solution of 0.200 M potassium dichromate (K2Cr2O7), you can use the formula: [ \text{mass} = \text{molarity} \times \text{volume} \times \text{molar mass} ] Substituting the values, you get: [ \text{mass} = 0.200 , \text{mol/L} \times 0.150 , \text{L} \times 294 , \text{g/mol} = 8.82 , \text{g} ] Therefore, you need to add 8.82 grams of solid potassium dichromate to prepare the solution.
How much glucose powder in .5 of water for a 1 molar solution?
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
How do you prepare 1 molar iodoacetamide solution?
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
How many grams of ammonium sulfate are needed to make a 0.25 molar solution at a concentration of 6 molar?
To prepare a 0.25 M solution of ammonium sulfate (NH₄)₂SO₄, you first need to determine the molar mass of ammonium sulfate, which is approximately 132.14 g/mol. For a 0.25 M solution, you need 0.25 moles per liter. Therefore, to make 1 liter of a 0.25 M solution, you would need 0.25 moles × 132.14 g/mol = 33.04 grams of ammonium sulfate. If you want to prepare a solution at a concentration of 6 M instead, you would need a significantly higher amount, specifically 6 moles × 132.14 g/mol = 792.84 grams for 1 liter.
How is a 5 molar solution different than a 1 molar solution of koolaid?
They're actually exactly the same in that neither of them exists.
Why you can use 4.9035 g K2Cr2O7 to prepare 0.1 n solution?
To prepare a 0.1 N solution of K2Cr2O7, you need to calculate the molar mass of K2Cr2O7 and use the formula for normality. By dividing the given weight by the molar mass, you can determine the number of moles present, and then calculate the normality using the volume of the solution.
How do you make 0.25N K2Cr2O7 solution?
To prepare a 0.25N K2Cr2O7 solution, you would dissolve 12.43 grams of K2Cr2O7 in enough water to make 1 liter of solution. This will give you a molarity of 0.25N for potassium dichromate (K2Cr2O7) in the solution.
How prepare 0.1 n k2cr2o7?
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
How much solid potassium dichromate must be added to prepare 150 mL of 0.200 M solution of K2Cr2O7 (molar mass 294 gmol)?
To prepare a 150 mL (0.150 L) solution of 0.200 M potassium dichromate (K2Cr2O7), you can use the formula: [ \text{mass} = \text{molarity} \times \text{volume} \times \text{molar mass} ] Substituting the values, you get: [ \text{mass} = 0.200 , \text{mol/L} \times 0.150 , \text{L} \times 294 , \text{g/mol} = 8.82 , \text{g} ] Therefore, you need to add 8.82 grams of solid potassium dichromate to prepare the solution.
How many grams of potassium are present in 21.6 g of K2Cr2O7?
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
How many grams of potassium are in 24.1 g of K2Cr2O7?
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
How do you prepare a molar solution?
To **prepare a molar solution**, you follow a clear step-by-step process based on the *definition of molarity*: [ M = \frac{\text{moles of solute}}{\text{liters of solution}} ] 🔹 Steps to Prepare a Molar Solution **Determine the desired molarity (M)** Decide the concentration you need — for example, a 1.0 M NaCl solution. **Calculate the moles of solute required** [ \text{moles of solute} = M \times \text{volume of solution (in liters)} ] Example: To make **1.0 L of a 1.0 M NaCl** solution → need **1.0 mol NaCl**. **Convert moles to grams** Use the molar mass of the solute: [ \text{mass (g)} = \text{moles} \times \text{molar mass (g/mol)} ] For NaCl (58.44 g/mol): ( 1.0 mol \times 58.44 g/mol = 58.44 g ) **Weigh the solute accurately** Use a balance to weigh out 58.44 g NaCl. **Dissolve the solute** Transfer the solute to a **volumetric flask** or beaker. Add **distilled water** to dissolve it (not to the full volume yet). Stir until completely dissolved. **Dilute to the final volume** After the solute dissolves, add more distilled water **until the total volume equals the desired final volume** (e.g., up to the 1 L mark in the flask). **Mix thoroughly** Stopper the flask and invert it several times to ensure uniform mixing. ✅ **Example Summary:** To make **1 L of 1 M NaCl solution**: Calculate: ( 1 mol/L × 1 L = 1 mol ) Convert to grams: ( 1 mol × 58.44 g/mol = 58.44 g ) Weigh 58.44 g NaCl. Dissolve in ~800 mL water. Add water up to the 1 L mark. Mix thoroughly. Would you like me to show how to prepare a specific molar solution (e.g., 0.5 M HCl or 2 M NaOH)? Buy Verified TikTok Accounts Buy Verified TikTok Accounts can be incredibly valuable for creators and brands. When your profile is verified, that adds an immediate sense of credibility. This encourages visibility and trust from both the creator and the user to engage and view additional content. The site is highly saturated, and difficulty arises without high levels of followers. A verified account provides you a competitive advantage, which can lead to beneficial collaboration and sponsorships that may not have been possible without it. If you need good quality and high quality accounts please contact us. If you face any problem you can contact us. we are online 24/7 hours WhatsApp: +18702143223 Telegram: @usithornet
Does molarity and normality is same in K2Cr2O7?
No, molarity and normality are not the same in K2Cr2O7. Molarity is the concentration of a solution expressed in moles of solute per liter of solution, while normality is a measure of concentration based on the equivalents of a solute in a solution. In the case of K2Cr2O7, as it has more than one ion that can undergo reaction, the normality would be different from the molarity.
How many grams of CoCl2 6H2O are needed to prepare 50.0ml of a 0.30M CoCl2 solution?
To determine the mass of CoCl2 6H2O to prepare a 0.30M solution in 50.0ml, we first calculate the molar mass of CoCl2 6H2O. The molar mass is 237.93 g/mol, so for a 0.30M solution in 50.0ml, we can use the formula: mass = molarity x volume (L) x molar mass. Therefore, the mass of CoCl2 6H2O needed is 3.57 grams.
How many grams of oxygen will be in 2 moles of potasium dichromate?
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
How much glucose powder in .5 of water for a 1 molar solution?
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
How do you prepare 0.2M of anhydrous of sodium thiosulphate?
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
