To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
100 grams
30.115*10^23 molecules
708.1mg
I Don't knows Sorry