You will end up with no current output on the secondary side of the CT.
When a capacitor is connected to a circuit, the current flow through the capacitor initially increases and then decreases as the capacitor charges up.
What happens to the current in a circuit as a capacitor charges depends on the circuit. As a capacitor charges, the voltage drop across it increases. In a typical circuit with a constant voltage source and a resistor charging the capacitor, then the current in the circuit will decrease logarithmically over time as the capacitor charges, with the end result that the current is zero, and the voltage across the capacitor is the same as the voltage source.
Because of fire
An open circuit, by definition, has no continuity, therefore there is no current flow. A failed capacitor in an open circuit would have absolutely no effect.
What should happen is that the circuit-breaker should trip to cut off the current before the transformer becomes damaged by overheating.
When you apply DC directly to a capacitor, it charges to the value of the DC potential, and then there is (nearly1) zero current flow through the capacitor. If the capacitance is large enough, though, and the DC source has a low enough impedance, the current flow can be quite substantial, damaging things.The reason the equilibrium current is zero is that a capacitor resists a change in voltage, proportional to current and inversely proportional to capacitance...dv/dt = i/c... which makes the capacitor essentially a high pass filter, and a DC blocker.1 The equilibrium current is "nearly" zero because, in our non-ideal world, every capacitor has some leakage current. Practically, the current is zero - from a purist perspective, it is not.
The circuit becomes a pure resistance circuit where current and voltage are in phase with each others.
When the frequency of a transformer is increased, the core losses of the transformer increase due to increased eddy current losses and hysteresis losses. This results in a rise in temperature of the transformer. Additionally, higher frequency can affect the impedance of the transformer and alter the voltage regulation and efficiency.
For a long time, The capacitor will be charged to the voltage of the DC battery, the positive side of the capacitor touching the positive terminal of the battery. Not much DC current will conduct, except for some tiny leakage current due to imperfection of the cap. The battery will be drained eventually.
As long as you don't exceed the breakdown voltage of the capacitor ... which is marked right on it ... DC voltage on it produces NO current flow through it. Only AC 'appears' to flow through a capacitor, and even that appearance is bogus when you really get down to it.
The wattmeter will read downscale (backwards).
A: A transformer is a PASSIVE ac component applying dc to it the wires resistance would be the only limiter for current flow. Usually a common transformer will burn up fast or slowly depends on power applied