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2 NaOH(aq) + CO2(g) = Na2CO3(aq) + H2O(l)
This solution contain 26,3 g NaOH.
The answer is 0,625 moles.
Methyl orange shows yellow color in an NaOH solution.
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
Chloroform, CHCl3 is slightly acidic in nature so with a strong base like NaOH it losses proton (H+) and forms a carbanion. CHCl3+ NaOH -----> (CCl3)1-Na1+ + H2O
2 NaOH(aq) + CO2(g) = Na2CO3(aq) + H2O(l)
This solution contain 26,3 g NaOH.
The answer is 0,625 moles.
It is possible only if you evaporate the water.
The concentration of this solution (in NaOH) is 40 g/L.
standardization of NaoH
40 grams, this is the 1M NaOH standard laboratory solution.
Methyl orange shows yellow color in an NaOH solution.
100 g of solution containing 50 g of NaOH.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .