A: If put in series current will decrease if put in parallel current will increase assuming the input voltage remains the same
nothing
Nothing.
When two light bulbs are in place, there will be a circuit created where electricity can flow through both bulbs. If the circuit is intact and the bulbs are functioning, they will both light up. If one of the bulbs is faulty or the circuit is broken, then both bulbs may not light up.
Adding more batteries to a circuit with light bulbs will increase the brightness of the bulbs. This is because the additional batteries will provide more voltage, which allows for a higher current to flow through the circuit. As a result, the bulbs will emit more light due to the increased energy supplied.
A: There is no such a thing as simple circuit if the bulbs are put in series the light will dim if put in parallel both bulbs will light up the same provided the source can sustain the power increase
The total current in the circuit will decrease.
In a parallel circuit, adding more light bulbs does not decrease the brightness of the existing bulbs. Each bulb operates independently and receives the full voltage of the power source, so their brightness remains consistent regardless of how many bulbs are added. However, the total current drawn from the power source will increase with each additional bulb.
By adding more light bulbs
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
In a series circuit, all bulbs are necessary to complete the circuit. If one bulb goes out, the circuit is broken, so none of the bulbs would light up.
Yes, light bulbs can be powered by a parallel circuit.
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.