As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
No. Although there is a voltage drop across the filament of an incandescent light bulb, the amount of current flowing out is identical to what flows in: current in = current out. That is an important fact to always keep in mind when solving simple electrical circuits: the sum of the currents flowing into a node equals the sum of the currents flowing out of it.
current will decrease
As an example imagine a 60 W light bulb running off 120 V. The current will be 1/2 A. Now assume that you put a second 60 W bulb in series with the first. Now the resistance of the single 60 W bulb is 240 Ohms. The 1/2 A flowing through the bulb heats up the filament wire and causes an amount of light to be emitted. Resistance in series adds, so the total resistance for two of the bulbs in series is 480 Ohms and by Ohms law V = I x R, the current through each bulb will be 1/4 amp and hence the bulbs will be less bright.
A circuit with a 2 ohm resistor and a 4 ohm resistor in series with a 12 volt battery will have 2 amps flowing through each resistor. The current is the same in each resistor because they are in series, and a series circuit has constant current throughout.
When light bulbs are turned on, they typically use up around 0.5 to 1 ampere of current.
If switch S is opened, the current through bulb 2 will decrease and eventually stop flowing because the circuit is broken. Bulb 2 is connected in parallel to bulb 1 and both bulbs have the same voltage across them, so when the circuit is opened, current stops flowing through both bulbs.
If you add more cells in series with the bulbs, the current will increase as the voltage across the bulbs increases. If you add more cells in parallel with the bulbs, the current will stay the same because the voltage of the cells does not increase when they are added in parallel.
The total current provided by the battery increases as more bulbs are added to a parallel circuit. This is because each branch in a parallel circuit receives the full voltage of the battery, leading to more current flowing through each branch as more loads (bulbs) are added.
In a series circuit, the current passing through each component, like the light bulbs, is the same. This means that both light bulbs would have the same current flowing through them. If one light bulb were to burn out, current flow through both bulbs would stop.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
Fluorescent light bulbs flicker because of fluctuations in the electrical current flowing through the bulb. This can be caused by issues with the bulb itself, the ballast, or the electrical connection.
Voltage remains constant; current increases.
current in series always stays the same
It is unclear what type of circuit you are referring to, so I'll give both answers.parallel, current increases until too many bulbs have been added, then circuit breaker pops and current drops to zero.series, current decreases and all bulbs dim.
Current in a series circuit is the same throughout the circuit. Voltages are additive. Voltage in a parallel circuit is the same throughout the circuit. Currents are additive.
When more bulbs are added to a parallel circuit, the total current in the circuit increases because each bulb provides an additional path for current to flow. This is because in a parallel circuit, the current is divided amongst the branches, so adding more branches (bulbs) will increase the total current.