Since the SAME electrons have to go through both light bulbs, the current in both light bulbs will be the same (Kirchhoff's current law).
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
In a parallel circuit, each bulb receives the full voltage of the power source, so all bulbs shine at their full brightness. In a series circuit, the brightness of each bulb decreases as more bulbs are added because the voltage is shared among all bulbs.
When you unscrew a light bulb in a series circuit, the circuit will break and all the other light bulbs in the circuit will turn off. This is because in a series circuit, the current flows through each component in succession, so removing one component interrupts the flow of current to the rest of the circuit.
parallel circuit: Providing that the breakage does not result in a short circuit the other bulbs will still light. series circuit: If the breakage results in a short circuit through the bulb the other bulbs will light more brightly. If the breakage results in a breakage of the connection through the bulb then the other bulbs will not light.
Yes, a circuit with two light bulbs connected in series can light up. Current flows through the first light bulb, then through the second, allowing both bulbs to illuminate. If one bulb burns out, however, both bulbs will go out.
As the number of bulbs in a series circuit increases, the current decreases. As the number of bulbs in a parallel circuit increases, the current increases.
All the bulbs will go out. In a series circuit, the current at all points is the same. This is Kirchoff's Current Law. If you loosen or remove a bulb in a series circuit, the current at that bulb becomes zero, and by Kirchoff's Current Law, the current in every part of the circuit also becomes zero.
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
the same current flows through both light bulbs
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
current in series always stays the same
Bulbs in a parallel circuit draw the same amount of current, so each will display the same brightness. Bulbs in a series circuit share the current so all bulbs will appear dimmer.
The total current in the circuit will decrease.
By adding more light bulbs
In a parallel circuit, each bulb receives the full voltage of the power source, so all bulbs shine at their full brightness. In a series circuit, the brightness of each bulb decreases as more bulbs are added because the voltage is shared among all bulbs.
When you unscrew a light bulb in a series circuit, the circuit will break and all the other light bulbs in the circuit will turn off. This is because in a series circuit, the current flows through each component in succession, so removing one component interrupts the flow of current to the rest of the circuit.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.