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Capacitors have always been added on both power lines and telephone lines to compensate for the build up of inductive reactance in long runs of wire.
For capacitors connected in parallel the total capacitance is the sum of all the individual capacitances. The total capacitance of the circuit may by calculated using the formula: where all capacitances are in the same units.
It becomes harder and tougher. Manganese steel is what soldiers helmets were made out of in WW II.
It will be lowered with the result that the steel becomes more brittle.
A capacitor joined with a sinusoidal voltage source will bring about a relocation current to move through it. For the situation that the voltage source is V0cos(ωt), the displacement current can be communicated as: I = C \frac{dV}{dt} = - \omega {C}{V_\text{0}}\sin(\omega t) At sin(ωt) = - 1, the capacitor has a most extreme (or top) current whereby I0 = ωCV0. The proportion of crest voltage to crest current is because of capacitive reactance (signified XC). X_C = \frac{V_\text{0}}{I_\text{0}} = \frac{V_\text{0}}{\omega C V_\text{0}} = \frac{1}{\omega C} XC methodologies zero as ω methodologies endlessness. In the event that XC approaches 0, the capacitor looks like a short wire that emphatically passes current at high frequencies. XC approaches boundlessness as ω methodologies zero. On the off chance that XC approaches unendingness, the capacitor looks like an open circuit that ineffectively passes low frequencies. The current of the capacitor may be communicated as cosines to better contrast and the voltage of the source: I = - {I_\text{0}}{\sin({\omega t}}) = {I_\text{0}}{\cos({\omega t} + {90^\circ})} In this circumstance, the current is out of stage with the voltage by +π/2 radians or +90 degrees.
A: Any additional capacitor added in parallel will effectively increase to total capacitance by that value. Note that additional capacitor added must have the same voltage rating as the other
The total capacitance from capacitors that are connected in series are added up inversely; 1/Ctotal = 1/C1 + 1/C2 + ... + 1/Cn, where Cn is the capacitance of the nth capacitor.
A: All capacitors are added in value for a total value. In series each capacitor value is divided into '1' and the fraction value is added to the next fraction and so on While in parallel the value increases in series the value decreases with each addition
happens
what happens if magnesium ribbions is added in acetic acid
what happens to molecules as energy is added the temperature increses
Nothing will happen you just wont be able to get that extra leveling if added weight or reduced, Yes you can drive with it off, wont hurt a thing.
This is not entirely true. In small power stations not connected to grids and wind turbines they usually use induction generators instead of synchronous for their capability of producing energy at varying rotor speeds and their price which is lower the synchronous generators. Before I tell you why they use synchronous in big power stations connected to the grid you must know that usually you have more than one power plant connected to the grid. And if you want the power of each power plant to be added to the grid you need the all the alternating currents to be in phase so the frequency must be the same. And as you probably know they are called SYNCHRONOUS generators because the speed of the rotor (the frequency) is the same as the AC supply current. So obviously it will be much easier to control the frequency of a synchronous generator and therefore easier to synchronize with the grid.
An autotransformer does not normally use any capacitors as it is a transformer with one winding and the lower voltage is taken from a tap part-way up the winding. A capacitor could be added if there is a concern about the power factor presented by the autotransformer to the supply.
it desolves
nothing happens but you can add iodine then it will change coulur
nothing happens