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True or false the equation N2 plus 3H2 means that 1g of N2 reacts with 3g of H2 to form 2g of NH3?
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
What is the chemical equation liquid nitrogen reacts with an excess of hydrogen gas?
3 H2 + N2 = NH3
How do you balance N2 plus H2yeildsNH3?
(N2) + 3(H2) = 2(NH3)
2 liters of N2 and 2 liters of H2 on complete reaction would give liter of NH3?
The reaction of 2 liters of N2 and 2 liters of H2 to form NH3 is based on the balanced equation: N2 + 3H2 -> 2NH3. Since 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3, 2 liters of N2 and 2 liters of H2 would produce 2 liters of NH3 following the stoichiometry of the balanced equation.
When 3 moles of N2 reacts with 2 moles of H2 the number of produced moles of ammonia equal?
The reaction between nitrogen and hydrogen to form ammonia is: N2 + 3 H2 → 2 NH3 The above is the reaction for the Haber process in the industrial synthesis of ammonia. For a given proportion of 3 N2 to 2 H2 (or in ratio terms equivalent to 4.5 N2 to 3 H2), we see that H2 is the limiting reactant. Thus according to the stoichiometry of the reaction, 2 moles of H2 will form 1.33 moles of NH3.
What elements are oxidized and what are element are reduced N2 H2--NH3?
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.
A 7.1-g sample of N2 requires how many g of H2 for complete reaction?
To calculate the amount of H2 needed for the complete reaction with 7.1g of N2, you need to use the stoichiometry of the balanced chemical equation. Since the reaction is not specified, I'll assume it's the formation of ammonia (NH3) from N2 and H2. Using the balanced equation, calculate the molar ratio of N2 to H2. Then convert 7.1g of N2 to moles, and finally use the molar ratio to determine the grams of H2 required.
How many molecules of H2 react with each molecule of N2?
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
Identify the reactants of H2 N2NH3?
The reactants are hydrogen and nitrogen.
What is the limiting reactant when 3.41 g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produced?
The reaction for the Haber process isN2 + 3 H2 ⇌ 2 NH3Amount of N2 = 3.41/28.0 = 0.122molAmount of H2 = 2.79/2.0 = 1.40molAccording to the stoichiometry of the reaction, 1 mol of N2 reacts with 3 mol of H2. 0.122mol of N2 will therefore react with only 0.366mol of H2, but there is 1.40mol of H2 available. Thus H2 is in excess and N2 is the limiting reactant.1mol of N2 reacts to form 2 mol of NH3.Under the maximum possible yield, 0.122mol of N2 reacts to form 0.244mol of NH3.Mass of NH3 = 0.244 x 17.0 = 4.15g
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
What is chemical equation for ammonia?
The chemical equation for the formation of ammonia is N2 + 3H2 → 2NH3. This equation represents the reaction between nitrogen gas (N2) and hydrogen gas (H2) to produce ammonia (NH3). The balanced equation shows that one molecule of N2 reacts with three molecules of H2 to form two molecules of NH3.
