A cow has 4 legs; therefore, 4 legs times 8 cows equals 32.
A chicken has 2 legs; therefore, 2 legs times 10 chickens equals 20.
So, 8 cows have more legs than 10 chickens.
There are 40 animals in a farm cows and chickens and the total legs is 100 and the answer is 30 chickens and 10 cows. Use Guess and Check Method. No of Cows No of Chickens Total number of Legs Total number of animals Check 20 × 4 = 80 20 x 2 = 40 120 40 X 15 x 4 = 60 25 x 2 = 50 110 40 X 10 x 4 = 40 30 x 2 = 60 100 40 √ There are 10 cows and 30 chickens in the farm.
This can be done in your head: If all animals were cows there would be 321 legs. Every cow replaced by a chicken reduces this figure by one.The total reduction is 97 (321 - 224) so there are 97 chickens (and 10 cows)Check legs: (97 x 2) + (10 x 3) = 194 + 30 = 224. QED
Assuming that all of the animals are "normal" (no amputees, 2-headed mutations, etc.) : 15 cows (15 x 4 = 60 legs) plus 5 chickens (5 x 2 = 10 legs) gives a total of 20 heads and 70 legs.
10 cows didn't eat there were 30 chickens.
There are 30 cows 20 ate chickens 28 is the answer 20 ate
cows been found with 6 legs but idk about 10 legs...
twenty six legs in all 4 pigs x 4 legs = 16 legs 3 chickens + 2 monkeys = 10 Total = 26 legs.
60
chickens chickens
There are 61 horses and 10 chickens on the farm.
10^99
5 cows, 1 pig, and 94 chickens