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What height from the centre of earth the value of g is half of its value on the surface of earth?
Wiki User
∙ 13y ago
gravity follows an inverse squared law. at twice the distance it would be a quarter of G.
1/g2 = 1/2. so the distance would be the square root of 2 (or 1.4). 1.4 x earths radius of 6366 km would be 9003 km
Wiki User
∙ 13y ago
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What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
Where the gravitational field strength is maximum?
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
What is the effect of depth on the earth on the value of g?
As soon as you go below the surface, it will decrease (dont ask for the calculations) until at its centre where acceleration due to gravity will be 0.
Value of accelaration due to gravity at the centre of the earth?
Zero.
What is the earth's gravity in terms of acceleration?
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
At what altitude above the earth surface the value of 'g' reduces to half of its value at the surface?
at about 9km above the surface of the sea.
How strong is the Martian gravity?
At the surface, 38% of its value at the Earth's surface.
What will happen to value of g if compound pendulum is taken nearer to the centre of the earth?
The acceleration of gravity decreases as the observation point is taken deeper beneath the surface of the Earth, but it's not the location of the compound pendulum that's responsible for the decrease.
How does the force of gravity on Jupiter compare to the force of gravity in Earth?
At the surface, it is 2.64 times its value at the Earth's surface.
What distance from centre of earth where value of g is half?
You haven't said 'half' of WHAT .I'll assume that you mean "half of what it is on the surface", andI shall now proceed to answer the question that I have invented:(x/earth radius)2 = 2x = (earth radius) times sqrt(2) =9,010 km (5,599 miles) from the center2,639 km (1,640 miles) from the surface(all rounded)
How much more is the level of gravity on jupiter than on earth?
The acceleration of gravity at the 'surface' of Jupiter is 2.639 times its value at the Earth's surface.
What is the value of null point where the value of gravitational force of earth equals the gravitational force of moon?
It is approximatly 3.42*10^8 M away from the centre of mass of the earth
