As soon as you go below the surface, it will decrease (dont ask for the calculations) until at its centre where acceleration due to gravity will be 0.
Because the value of "g" varies directly with the sum of the masses of the two bodies acted upon by the force of gravity. If you go inside the earth, only part of the mass of the earth will be attracting you toward its center; the mass of the part of the earth that is farther from the center than you are will be attracting you away from the center. If it were possible to reach the center of the earth, the value of "g" would reach zero because the mass of the earth would be acting upon equally you in all directions.
G
0.376 g
First of all let us make a correction. It is not weight of the earth it is only MASS of the earth. By gravitational field concept we arrive at one expression for acceleration due to gravity as g = G M/ R2 G - universal gravitational constant. R-radius of the earth. g-of course measured by the simple pendulum experiment. Knowing g, G, R, we can compute M ie mass of the earth as M = gR2/G Cavendish was the first scientist who found the mass of the earth. But we say so colloquially that he was the first man who weighed the earth.
The Earth's surface, where it is not water, is called the ground.
G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
Changing the length of a pendulum or the mass of its bob has no effect on g; g is a constant, always equal to 9.8 meters per square second near the surface of Earth.
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
i think value of g becomes zero
g
Zero.
Zero.
The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.
The gravitational force decreases when you go deeper within the Earth. That is because part of the Earth will be above you, and therefore pull you up. your wrong my friend: in Thermodynamics by Cenjel: It is interesting to note that at locations below sea level, the value of g increases with distance from the sea level, reaches a maximum at about 4500 m, and then starts decreasing. (What do you think the value of g is at the center of the earth?)
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
yes it can change....