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It depends on the voltage rating.
Look on the light bulb for the voltage and the power in watts. Then divide the watts by the voltage and that gives the amps. Some CFL bulbs also state the current as well as the voltage and power, which is because they can have a poor power factor.
What is the voltage and current of an integrated cicuit
yes
A zener diode with a rating of 500 mW will pass 50 mA at 10 V. (Power = voltage times current)Note: The question appears mis stated, in that it states a rating of 500 MW, not 500 mW. To my knowledge, there is no zener with a rating of 500 MW.
225W
It depends on the voltage rating.
Power = Voltage x Current P=V.I Power (in Watts) = 110V x 8.70A = 957W (Appx. 1kW) - Neeraj Sharma
how much voltage does a monitor takes to operate
Look on the light bulb for the voltage and the power in watts. Then divide the watts by the voltage and that gives the amps. Some CFL bulbs also state the current as well as the voltage and power, which is because they can have a poor power factor.
What is the voltage and current of an integrated cicuit
Wattage or power rating of a product can be calculated by multiplying voltage rating and current rating. (Power = Voltage x Current). e.g. if device is working at 12V and 2A is the current rating. It is 24Watt. Since Voltage = Current x Resistance , for a resistive load power can also be calculated by Power = Current x Current x Resistance = I^2 x R = I square R
True power is expressed in watts, so the true power of your heater is its kilowatt rating at its rated voltage. Variations in voltage will result in variations in its power. Assuming its resistance remains roughly constant for variations in temperature, then True Power = V2/R.
350
At a specific voltage the higher the amperage the higher the rated horsepower of the motor. You will see the amperage rating used when manufactures sell hand tools. A saw that draws 12 amps, it is stated, is better than the saw that draws 9 amps. As the question stands a comparison can not be made between voltage and amps.
yes
A zener diode with a rating of 500 mW will pass 50 mA at 10 V. (Power = voltage times current)Note: The question appears mis stated, in that it states a rating of 500 MW, not 500 mW. To my knowledge, there is no zener with a rating of 500 MW.