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What if your statistics instructor wants you to determine a confidence interval estimate for the mean test score for the next exam In the past the test scores have been normally distributed with a mea?
God3367
74.2 - 1.96 x 30.9 / sqrt 30
= 63.14
72.2 + 1.96 x 30.9 / sqrt 30
= 85.26
answer 63.14 to 85.26
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∙ 10y ago
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What do results tell you with regard to whether the data is normally distributed?
Your question may be a little overly complex. Usually you start with some degree of confidence that the variable(s) you are studying are normally distributed; you don't do an experiment and wait for the results to tell you. Your confidence that a variable is normally distributed helps you to determine whether or not your results are significantly different from what you would expect by chance. If I have missed the meaning of your question, my apologies.
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