your question makes no sense!
In the reaction given, the spectator ions are the ions that do not participate in the actual chemical change. In this case, the Na⁺ ions remain unchanged on both sides of the equation, so they are the spectator ions. The OH⁻ and H⁺ ions combine to form water (H₂O), while the Cr species is also involved in the reaction, potentially forming a compound.
Acids will give H+ ions.
Hydrogen ions (H+) can be thought of as protons.
It accepts H+ ions.
The representation H2O H plus plus OH signifies the dissociation of water molecules into hydronium ions (H+) and hydroxide ions (OH-) in aqueous solution. This is the auto-ionization of water where some water molecules act as both acids (donating H+ ions) and bases (accepting H+ ions). The concentration of H+ and OH- ions in pure water is equal at 10^-7 M.
To derive the net ionic equation, we first identify the species involved in the reaction. The complete ionic equation shows that we have 2 H⁺ ions, 1 SO₄²⁻ ion, 1 Ca²⁺ ion, and 2 I⁻ ions. When calcium sulfate (CaSO₄) forms, the net ionic equation simplifies to: Ca²⁺ + SO₄²⁻ → CaSO₄(s). The H⁺ and I⁻ ions are spectator ions and do not appear in the net ionic equation.
Cellular respiration = H+ Cellular metabolism = H+ Anaerobic respiration = H+ Incomplete Oxidation of fatty acids = H+ Hydrolisis of phosphoprotiensn and nucleic acids = H+ H+ = Hydrogen Ion
No, acids do. Bases produce OH- ions
H plus ions would not flow
In the reaction (2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \rightarrow CaSO_4 + 2H^+ + 2I^-), the spectator ions are those that do not change during the reaction. Here, the ( H^+ ) ions and ( I^- ) ions are present on both sides of the equation and do not participate in the formation of the precipitate ( CaSO_4 ). Therefore, the spectator ions are ( H^+ ) and ( I^- ).
H+ ions would flow out of the mitochondrion
H plus ions would not flow