Ionization of water molecule .
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.
OH - ? Strangely enough it is water! H2O.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The conjugate acid for the base OH- is H2O. This is because when OH- accepts a hydrogen ion (H+), it forms water (H2O).
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.
Yes, H2O is amphoteric so it can lose H+ and become hydroxide. Hydroxide is represented as OH-.
The concentration of OH- decreases as the concentration of H+ increases. This is beacause there is an equilibrium H2O <-> H+ + OH- and therefore the [H+][OH-] is a constant
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Water , This is a poorly written chemical equation for the formation/dissociation of water. H^(+) + OH^(-) H2O(l)
The equation for the dissociation of water is: H2O ↔ H+ + OH-
OH - ? Strangely enough it is water! H2O.
(OH- is a base) (H+ is an acid) Therefore by adding water to HSO3, the OH- ion is produced therefore it is an Arrhenius base.
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
The molecule formed will be water. H+ + OH- = H2O.
In the reaction involving NH3 (ammonia) and H2O (water), the two Brønsted-Lowry acids are H2O and NH4+ (ammonium ion). H2O donates a proton (H+) to NH3, forming NH4+ and OH-. Thus, H2O acts as an acid by donating a proton, and NH4+ is the resultant acid formed in the reaction.