Ionization of water molecule .
H2O, or water
H2O=H+ +OH- Ka=[H+][OH-]/[H2O] Ka[H2O]=[H+][OH-] [H2O]=Constant Ka=[H+][OH-]=Kw=1*10-14
H+ + oh- ---> h2o
Think of water as HOH, which is basically a H+ ion and an OH- ion. So then, in solution, the reaction looks like this: Na+ + OH- + H+ + Cl- ----> Na+ + Cl- + H+ + OH- and then if we put the ions together, we get NaOH + HCl ----> NaCl + H2O.
HOH or H2O is water.
Yes, H2O is amphoteric so it can lose H+ and become hydroxide. Hydroxide is represented as OH-.
The concentration of OH- decreases as the concentration of H+ increases. This is beacause there is an equilibrium H2O <-> H+ + OH- and therefore the [H+][OH-] is a constant
H2O, or water
H2O=H+ +OH- Ka=[H+][OH-]/[H2O] Ka[H2O]=[H+][OH-] [H2O]=Constant Ka=[H+][OH-]=Kw=1*10-14
H+ + oh- ---> h2o
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Think of water as HOH, which is basically a H+ ion and an OH- ion. So then, in solution, the reaction looks like this: Na+ + OH- + H+ + Cl- ----> Na+ + Cl- + H+ + OH- and then if we put the ions together, we get NaOH + HCl ----> NaCl + H2O.
HOH or H2O is water.
In neutralisation reactions H+ and OH- ions come from the dissociation of water, H2O, which is part of the solution.Water dissociates in equilibrium, shown as:H2O(l) H+(aq) + OH-(aq)
(OH- is a base) (H+ is an acid) Therefore by adding water to HSO3, the OH- ion is produced therefore it is an Arrhenius base.
oh
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)