Li+
Ca+2
I-
S-2
Cs+
The elements in calcium iodide are calcium and iodine.
The formula is CaI2 and is made of the elements calcium (Ca) and iodine (I).
Cesium chloride is ionic.
potassium and iodine
Total mass is 63.80+63.25 cesium fraction is 63.80/127.05=.5022 iodine fraction is 63.25/127.05=.4978 compound total is 35.76*.5022=17.96g cesium 35.76*.4978=17.80g iodine
The elements in calcium iodide are calcium and iodine.
a. carbon - 4 b. iodine - 12 c. calcium - 2 d. gallium - 3
Potassium. It has two extra shells than lithium.
The formula is CaI2 and is made of the elements calcium (Ca) and iodine (I).
Water is the compound. Iodine and calcium are elements, and air is a mixture.
Calcium Iodide, CaI2, contains calcium, Ca and iodine, I.
CsCl like NaCl is a salt. The cesium has an ionic bond with the chloride.
Calcium and krypton have 4 electron shells.Sulfur has 3 electron shells.Iodine has 5 electron shells.
Cesium chloride is ionic.
potassium and iodine
Name: Cesium IodideEmpirical formula: CsIIonic Formula: CS1I1
The calcium iodide is obtained by the reaction between calcium carbonate (CaCO3) or calcium oxide (CaO) and the hydroiodic acid (HI), not by a direct reaction of the elements.