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How many watts does an EPIRB transmit?
5 watts +/- 3 dB
32 db is equal to how many watts?
5
25dB equal to how many watts?
That depends on you. If you want, you can say 1 watt should be 0 dB.
How many watts is 2000 kw?
2,000 kw is 2,000 kilo watts is 2,000,000 watts
How many watts is in 2 amps?
It depends on the voltage.Amps times volts equal watts
If transmitter power is increased from 200 Watts to 400 Watts how do you convert to Db form?
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
If a 13 dB gain antenna has 2 watts of power at the input what is the effective radiated power?
40 watts
How many watts does an EPIRB transmit?
5 watts +/- 3 dB
How many watts is 98db?
It depends on the reference. If the reference electric power is P0 = 1 W (0 dB) then 98 dB equals 6309573444.8 Watts.
32 db is equal to how many watts?
5
How do you convert 13.936 dB to watts?
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
25dB equal to how many watts?
That depends on you. If you want, you can say 1 watt should be 0 dB.
Calculate the power out put of an amplifier that has an input of 15 μw and a gain of 25dB?
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
What is 3 dB?
3 dB is a way to describe the amount by which power increases when it doubles.1 dB = increase 26%2 dB = increase 58%3 dB = double4 dB = 2.51 times5 dB = 3.16 times6 dB = 4 times (3 dB + 3 dB = double double)7 dB = 5 times8 dB = 6.31 times9 dB = 8 times (3+3+3 = double double double)10 dB = 10 timesSimilarly-1 dB = decrease 26%-2 dB = decrease 58%-3 dB = halve-4 dB = decrease 2.51 times...etc...The equation is:dB change = 3 log2 ( final power / initial power )Edit:The more "official" equation used to compute a decibel Gain/Loss when comparing power values is this:GdB = 10*log10(Pout/Pin)Where GdB is the gain in power (if the value is negative, it means loss)and Pout is the power level seen at the outputand Pin is the power level seen at the inputAlso, 0 dB means no change in power.Note: If you're measuring an amplitude (like a Voltage or Current value), then the decibel equation increases by a factor of 2:GdB = 20*log10(Pout/Pin)So, to double an amplitude, a 6dB increase would be required.In other words, take the values at the top of this answer, and double the left side of the equation, and that's how it works with amplitudes.Lastly, it's important to understand that when multiplying in the linear world, you are adding in the decibel world. If you double a power level 2 times (e.g. 10 watts -> 20 watts -> 40 watts), you are multiplying 4 fold, but you are increasing by 6 dB (3dB + 3dB = 6dB).BUT if your talking about audio (sound) 1db is the smallest change in sound volume the human ear can detect.
What is 3(20 7)?
3 dB is a way to describe the amount by which power increases when it doubles.1 dB = increase 26%2 dB = increase 58%3 dB = double4 dB = 2.51 times5 dB = 3.16 times6 dB = 4 times (3 dB + 3 dB = double double)7 dB = 5 times8 dB = 6.31 times9 dB = 8 times (3+3+3 = double double double)10 dB = 10 timesSimilarly-1 dB = decrease 26%-2 dB = decrease 58%-3 dB = halve-4 dB = decrease 2.51 times...etc...The equation is:dB change = 3 log2 ( final power / initial power )Edit:The more "official" equation used to compute a decibel Gain/Loss when comparing power values is this:GdB = 10*log10(Pout/Pin)Where GdB is the gain in power (if the value is negative, it means loss)and Pout is the power level seen at the outputand Pin is the power level seen at the inputAlso, 0 dB means no change in power.Note: If you're measuring an amplitude (like a Voltage or Current value), then the decibel equation increases by a factor of 2:GdB = 20*log10(Pout/Pin)So, to double an amplitude, a 6dB increase would be required.In other words, take the values at the top of this answer, and double the left side of the equation, and that's how it works with amplitudes.Lastly, it's important to understand that when multiplying in the linear world, you are adding in the decibel world. If you double a power level 2 times (e.g. 10 watts -> 20 watts -> 40 watts), you are multiplying 4 fold, but you are increasing by 6 dB (3dB + 3dB = 6dB).BUT if your talking about audio (sound) 1db is the smallest change in sound volume the human ear can detect.
Convert 100W into decibels?
Given P = 100 watts. Reference sound intensity Po = 10^−12 W. Reference sound intensity level LPo = 0 dB. Get power level LP in dB when entering sound power P in watts. Power level LP = 10×log (P / Po) dB = 10×log (100 / 10^−12) = 140 decibels (dB).
Calculate the power out put of an amplifier that has an input of 15wand a gain of 25dB?
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 Watts x 316.2 = 4.7kW If you want to work in dB, then convert 15 watts to dB: 10 * log |P| = dB = 10*log |15| = 11.76dB so the output is 11.76 + 25 = 36.76dB
