legs on a snake
n = 1 l = 0 m = 0 s = +1/2 and s = -1/2
Examples: #include <iostream> #include <string> using namespace std; int main() { string st = "hello world!"; cout << st << endl; char c[] = "hello world!"; cout << c << endl; char a[13] = {'h','e','l','l','o',' ','w','o','r','l','d','!' }; cout << a << endl; char * s; s = ( char * ) malloc( 13 ); memset( s, 0, 13 ); s[0] = 'h'; s[1] = 'e'; s[2] = 'l'; s[3] = 'l'; s[4] = 'o'; s[5] = ' '; s[6] = 'w'; s[7] = 'o'; s[8] = 'r'; s[9] = 'l'; s[10] = 'd'; s[11] = '!'; cout << s << endl; free( s ); return( 0 ); }
Potassium has an electronic configuration of 1s2, 2s2, 2p6, 3s2, 3p6, 4s1 The azimuthal quantum number of 0corresonds to an s subshell, 1 p subshell You can see that you have n=1, l=0 n=2, l=0; n=2, l=1 n=3, l=0; n=3, l=1, n=4, l=0
\ ] '[;[l;,'l[p[l[l[]l[l]/]['--0=-=- \ ] '[;[l;,'l[p[l[l[]l[l]/]['--0=-=- \ ] '[;[l;,'l[p[l[l[]l[l]/]['--0=-=-
The context-free grammar for the language L an bm n, m 0 can be represented as S - aSb .
Call the unknown larger number l and the unknown smaller number s. From the problem statement, l + s = 30 and l/s = s. From the second of these equations, after multiplying both sides by s, l = s2. substituting this value into the first equation yields s2 + s = 30, or s2 + s - 30 = 0. Factoring shows the latter expression to be equivalent to (s + 6)(s - 5) = 0, which is true when s = -6 or s = +5. The latter value of s leads to l = 25, which satisfies the conditions of the problem without negative numbers. The former value of s leads to l = 36, which also satisfies the conditions of the problem.
The correct answer is 2s. n = 2 corresponds the 2nd energy level and l = 0 corresponds to the s-subshell. You did not need to know ml = 0 to get the answer
The quantum number for Sodium is this: 1s2 => n = 1 l= 0 m=0 s = +/- 1/2 2s2 => n=2 l=0 m= 0 s = +/- 1/2 2p6 => n = 2 ; l = 1 , m = -1 , 0 , +1 s = +/- 1/2 3s1 => n = 3 l=0 m=0 s = + 1/2
n=4 s=-1/2 n=3 l=0
0 = O 1 = l or I 3 = E 4 = H 5 = S 7 = L 8 = B
Tonic solfa for Silent Night on the recorder: s l s m s l s m r r t d d s l l d t l s l s m l l d t l s l s m r r f r t d m d s m s f r d.
With the engine in the car...from left to right....Front head is L-S-S-L-S-L Rear head will be L-S-L-S-S-L