100 hg = hectogram
grams of mercury (Hg) 1 mole x 1 mole Avogadro's number (6.022 x 1023) of atoms 200.6 grams Hg 1 mole 200.6 grams Hg = x = ≈ 3.3311192-23 atoms Hg 1 mole 6.022 x 1023 atoms 6.022 x 1023 atoms
1 gram = 1 mL so;500 g = 500 mL34
Hg is an element. Mercury
2 bar = 59.06 inches of Hg 2 kPa = 0.59 in Hg
100 hg = hectogram
It takes more heat to melt 12.0 grams of Hg.
For this you need the atomic (molecular) mass of Hg(NO3)2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Hg(NO3)2=324.6 grams8.50 grams Hg(NO3)2 / (324.6 grams) = .0262 moles Hg(NO3)2
Mercury (Hg) has a density of 13.53 grams/milliliter. Therefore 38 ml of mercury weighs 514.14 grams. (38ml x 13.53g/ml)
Density = mass/volume ( Mercury is 13.534 grams/milliliter, and milliliter = cubic centimeter ) 13.534 g/ml = grams/9.1 cc (or ml) = 123.1594 grams of Hg ( Mercury) 123.1594 grams Hg (1 mole Hg/200.6 grams)(6.022 X 10^23/1 mole Hg) = 3.7 X 10^23 atoms of mercury
60.2/84.2 x 100% = 71.5%
10.1 grams
55.8 grams
71.5 %
grams of mercury (Hg) 1 mole x 1 mole Avogadro's number (6.022 x 1023) of atoms 200.6 grams Hg 1 mole 200.6 grams Hg = x = ≈ 3.3311192-23 atoms Hg 1 mole 6.022 x 1023 atoms 6.022 x 1023 atoms
246 grams is approx 1.23 moles of Hg(II) therefore the ratio is 1:1 so you need 1.23 moles of S which is approx 39.5 grams
Let us rewrite that equation. 2CO + 3HgCl2 >> 2CoCl + 3Hg 5.11 grams Mercury (1mole Hg/200.6g )(3mol HgCl2/3mol Hg)(271.5g/1mol ) = 6.92 grams of HgCl2