246 grams is approx 1.23 moles of Hg(II) therefore the ratio is 1:1 so you need 1.23 moles of S which is approx 39.5 grams
iron forms iron sulphide when reacts with sulphur, Fe + S = FeS in this reaction 32 g of sulphur require 56 g of iron so 16 g sulphur requires 28 g of iron.
The reaction is a limiting reactant problem since we are given the amounts of both reactants. With the excess of sulfur, all the lead will react to form lead sulfide. There won't be any sulfur left over. The analysis of the reaction mixture would show 28.44 g of lead sulfide produced, with excess sulfur not affecting the reaction.
Based on the balanced chemical equation 2Fe + 3S -> Fe2S3, the molar ratio of Fe to S is 2:3. First, convert the 48.0 grams of sulfur to moles, then use the molar ratio to find the moles of iron needed. Finally, convert the moles of iron to grams to determine the required amount of iron.
It is stable
Sulfur dioxide (SO2) can react with the oxygen in the air to produce sulfur teioxide (SO3). Either of these gases can react with water in the air to produce an acid, goes to SO2 sulfurous acid, SO3 goes to sulfuric acid.
iron forms iron sulphide when reacts with sulphur, Fe + S = FeS in this reaction 32 g of sulphur require 56 g of iron so 16 g sulphur requires 28 g of iron.
63 g of water are needed.
cannot answer without more info.
The reaction is a limiting reactant problem since we are given the amounts of both reactants. With the excess of sulfur, all the lead will react to form lead sulfide. There won't be any sulfur left over. The analysis of the reaction mixture would show 28.44 g of lead sulfide produced, with excess sulfur not affecting the reaction.
You need 145,337 g silver nitrate.
Sulfur does not react with water under normal conditions. However, when sulfur is in the form of sulfur dioxide (SO2) or hydrogen sulfide (H2S), these compounds can react with water to form sulfuric acid (H2SO4) and sulfurous acid (H2SO3) respectively.
mass H2O =49.2g
When aluminum and sulfur react, aluminum sulfide is produced.
128 g of oxygen are needed.
No. Sulfur is flammable, meaning it will react fairly easily with oxygen among other things.
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.
Based on the balanced chemical equation 2Fe + 3S -> Fe2S3, the molar ratio of Fe to S is 2:3. First, convert the 48.0 grams of sulfur to moles, then use the molar ratio to find the moles of iron needed. Finally, convert the moles of iron to grams to determine the required amount of iron.