1 meter = 3.28084 ft 330' = (330 / 3.28084) = 100.584 meters 165' = (165 / 3.28084) = 50.292 meters 4' = (4 / 3.28084) = 1.219 meters 330' x 165' x 4' = 100.584 m x 50.292 m x 1.219 m. This is what you asked for. You didn't ask for the volume of a block with dimensions of 330' x 165' x 4'. If that was what you're looking for, then -- you would have asked for it in "cubic meters", -- you would have stipulated that the block is a rectangular parallelapiped, i.e. has rectangular faces.
The lowest common multiple or LCM of 165 and 330 is 330. 165 x 2 = 330 330 x 1 = 330
165 x 2 = 330
The factors of 330 are 1, 2, 3, 5, 6, 10, 11, 15, 22, 30, 33, 55, 66, 110, 165, and 330. The factor pairs of 330 are 1 x 330, 2 x 165, 3 x 110, 5 x 66, 6 x 55, 10 x 33, 11 x 30, and 15 x 22.
330 = 2 x 165; = 2 x 3 x 55; = 2 x 3 x 5 x 11
r ≈ 4.2869 meters. V = 4/3 x pi x r3 solve for r => cube root ((v x (3/4))/pi) = r => cube root ((330 x (3/4))/pi) = 4.28688....
330 = 2 x 165, = 2 x 3 x 55, = 2 x 3 x 5 x 11
prime factors of 330: 2 X 165 = 2 X 5 X 33 = 2 X 5 X 3 X 11 prime factors of 330: = 2 X 3 X 5 X 11
These: 1, 2, 3, 5, 6, 10, 11, 15, 22, 30, 33, 55, 66, 110, 165, 330 Multiplied as: 1 x 330, 2 x 165, 3 x 110, 5 x 66, 6 x 55, 10 x 33, 11 x 30, 15 x 22
Assuming the playground is a perfect rectangle, the perimeter of the playground will be 330 meters.
1 x 330, 2 x 165, 3 x 110, 5 x 66, 6 x 55, 10 x 33, 11 x 30, 15 x 22
There are 0.0254 metres in one inch. Therefore, 330 inches is equal to 330 x 0.0254 = 8.382 metres.
.4 x 165 = 66