Iron oxides FeO and Fe2O3 react with acids in water and form salt and water so their behavior is just like bases, FeO + 2HCl = FeCl2 + H2O and Fe2O3+ 3H2SO4 = Fe2(SO4)3 + 3H2O
AL(OH)3 + 3HNO3 = AL(NO3)3 + 3H2O pinkey
so4
Al2O3 + 3H2SO4 = Al2 (SO4)3 + 3H2O We note that the molar ratios are 1:3::1:3 By Equivalence 0.89 : 2.67 ;; 0,89 :2.67 So moles of aluminium sulphate produced is 0.89 Using the equation moles = mass(g) / Mr Then mass = moles X Mr Refer to the Atomic Masses in the Periodic Table to find the Mr(Relative Molecular mass of Al2(SO4)3 Hence Al x 2 = 27 x 2 = 54 S x 3 = 32 x 3 = 96 O x (4 x 3 = 12) 16 x 12 = 192 54 + 96 + 192 = 342 ( Mr of Al2(SO4)3 ) Hence mass(g) = 0,89 X 342 = 304.38 g (This is the 100% theoretical yield. Experimentally it will be less , owing to losses in the filter paper , spillages etc., )
ITS: CH3COONa --> CH3COO- + Na+ Or if its CH3COONa . 3H2O --> CH3COONa + 3H2O
Semi nucleus acidic bases: 2 Fe(NH4)2(SO4)2*3H2O + H2O2 + K2C2O4 + 3H2C2O4 -> 2 K3Fe(C2O4)3*3H2O + 2(NH4)2SO4+ 2H2SO4 + 8H2O
No. CrS3 is chromium VI sulfide. Chromium III sulfate is Cr2(SO4)3
2NaAlO 2+3h2O
3H2O has 6 hydrogen atoms and 3 oxygen atoms.
SO4 is not a molecule. (SO4)2- is the sulfate ion.
Iron oxides FeO and Fe2O3 react with acids in water and form salt and water so their behavior is just like bases, FeO + 2HCl = FeCl2 + H2O and Fe2O3+ 3H2SO4 = Fe2(SO4)3 + 3H2O
so4
AL(OH)3 + 3HNO3 = AL(NO3)3 + 3H2O pinkey
Ba(SO4) + 2KCl
It is SO4 -2 named as sulphate ion.
BeC2O4 = 97.0 g/1 mol BeC2O4-3H2O = 151.0 g/1 mol 3.21 g BeC2O4-3H2O * 1 mol/151.0 g = 0.021258 mol BeC2O4-3H2O 0.021258 mol BeC2O4-3H2O * 97.0 g/1 mol = 2.06 g BeC2O4
The Sulfate, SO4