9q2 is the square of 3q - so 3q is the result of dividing 9q2 by 3q.
(p-3q) (p-3q) =p2+3pq+3pq+9q2 =p2+6pq+9a2 this is answer hehehhe (jhaylotte)
steps to solve 4(3q-q): =(4)(3q+-q) =(4)(3q)+(4)(-q) =12q-4 answer: 8q
3q+11+8q>99
P = 3a - 3q Add 3q to each side: P + 3q = 3a Double each side: 6a = 2P + 6q
3q = 18 q = 6
3q+11+8q>99
3q + 2z, although it could be 2*(3q+z)
(4p - 1)(3q - 2)
-1P-6Q-4 would be the answer if the space between the 3P and the second 3Q is another subtraction symbol.
Answer is 30pqr
(3)(q-11) = 3q-33