150 mA is.
The typical base-emitter gain (beta or hFE) of a CA3046 is 100, at an emitter current of 100ma. This translates to a base-collector gain (alpha) of 0.99.
Hi, the formula used to calculate this is P = U x I.where:P = Watt (W)U = voltage (V)I = current (A)You need 2 units to calculate the third one.Volt x current equals Watt240 V x 0.1 A (equals 100mA) = 24 WattAnswerThe equation for (true) power in an AC circuit is: P = (U I) x power factorSo, you need to know the power factor of the load in order to calculate the power. With the information you supply, you can only calculate the apparent power, expressed in volt amperes, which is the product of the supply voltage and the load current -using the figures that you supply, this will be 24 V.A.
Think of it this way: "P" is for Positive and "N" is for Negative So basically put a PNP Transistor Would use N to Switch P, in the name "PNP" or "NPN" the first character is for the polarity of the Collector-pin, the second for the Base-Pin, and the third for the Emmiter-pin. If you have a NPN Transistor you can`t just replace it with an PNP as the polarities differ. If you can find a way to change those polarities then sure it could work. I would say it`s best go out and buy a few of both so you have a few, otherwise if the application of the transistor is not in a high-current or high-voltage circuit try and find another circuit with the required type of transistor. Absolutely most transistors can be replaced with other similar transistors. Different transistors have different conditions they work by so you should do some research and replace it with another that is either the same or have approximately the same data. Example 1: A burned transistor with the data NPN, 45Volt, 100mA, 0,3Watt, need to be replaced. It is a discontinued transistor, so unfortunately no original spare part can be found. Check the max voltage of the circuit where it was. If the voltage is close to 35 volt, then you may want to replace it with a higher voltage transistor. If it is lower, say max 20 Volt, then you should be able to replace it with a lower voltage transistor. Check the type of circuit where it was. If in an audio amplifier, then you should choose a 'low noise' audio transistor. Look at the NPN transistors you can get hold of and make your choice based on similar or more current, similar or more wattage, similar or lower or even higher voltage. Most small signal transistors are interchangeable if you follow these steps. Even most power transistors are interchangeable but you should make an extra effort and check/match the HFE Data on the transistor too. Normally no need for an exact match at all.
yes
sure, no problem! The power supplying device is rated as to its MAXIMUM current delivering capacity, so 100ma being less than 650ma, you could run up to 6 of those devices in parallel with that adapter. You should not try to run a 650ma device with a 100ma supply though.
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.
100 hours.
No. an AC adapter will not work for equipment that needs DC.
120 volts. Probably won't kill you, but it isn't pleasant.
No you should not do that. It will damage the battery and the battery will explode.
No. Both the voltage and the current are too low.
No, if the device needs 700mA of current, your power adapter cannot supply adequate current.
150 mA is.
It looks like you answered your own copy-and-pasted question.
Yes. Yes, you can replace a transformer with one that has a higher current rating. The load on the transformer should be less than 200mA because presumably that is what the circuit was designed for. Since the current through the transformer should be less than 200mA, the 500mA transformer will not be damaged. The opposite is not true. You should not replace a 200mA rated transformer with a 100mA transformer, for example. If the current exceeds 100mA, the transformer could fry.