benzen ch2br
Cyclohexane can be converted into benzene by catalytic dehydrogenation in the presence of oxides of D block for ex V2O5, Cr2O3 etc. Cyclohexane when heated at 6000C in presence of Al2O3-Cr2O3 gives benzene.
Ethylbromide is the name of the compound CH3-CH2-Br.
Ethene has a very reactive double bond, and if mixed with bromine in organic solvent, it will undergo an addition reaction, where the two bromine atoms will adjoin onto the ethane molecule (because the double bond has broken, it now becomes an alkane (ethane) - more specifically it will form 1,2 - dibromoethane. C2H4 (g) + Br2 (tetrachloromethane) -------------------> CH2Br-CH2Br (aq) However, when bromine is dissolved in water instead, HOBr(aq) will be formed, subsequently the reaction becomes: C2H4 (g) + HOBr (aq) -------------------> HO-CH2-CH2Br (aq) Still, the brownish - reddish colour of the bromine water will decolourise. This is a useful way of distinguishing between alkanes and alkenes of similar molecular weights. ***RS**
yes there are 3 isomers. CHBr=CHBr, HCBr=HCBr, BrCBr=CH2(double bonded CH2 onto the C as well
benzen ch2br
R-choh-ch3 +h2so4 -> R-ch=ch2 R-ch=ch2 + HBr -> R-ch2-ch2Br R-ch2-ch2Br + H2O -> R-ch2-ch2oh + HBr
R-choh-ch3 +h2so4 -> R-ch=ch2 R-ch=ch2 + HBr -> R-ch2-ch2Br R-ch2-ch2Br + H2O -> R-ch2-ch2oh + HBr
Cyclohexane can be converted into benzene by catalytic dehydrogenation in the presence of oxides of D block for ex V2O5, Cr2O3 etc. Cyclohexane when heated at 6000C in presence of Al2O3-Cr2O3 gives benzene.
Ethylbromide is the name of the compound CH3-CH2-Br.
The Electrophilic Addition Reaction is when the attacking species during the addition reaction is"Electrophile", it is called "electrophilic addition reaction". Examine: (+) (-) (+) (-) (+) (-) CH2Br-CH2BràH2C-CH2+BrBr-àH2C=CH2+Br2-
The compound CH2=CH-CH=CH2 when reacts with HBr gives 1,4 addition product, CH3-CH=CH-CH2Br
Ethene has a very reactive double bond, and if mixed with bromine in organic solvent, it will undergo an addition reaction, where the two bromine atoms will adjoin onto the ethane molecule (because the double bond has broken, it now becomes an alkane (ethane) - more specifically it will form 1,2 - dibromoethane. C2H4 (g) + Br2 (tetrachloromethane) -------------------> CH2Br-CH2Br (aq) However, when bromine is dissolved in water instead, HOBr(aq) will be formed, subsequently the reaction becomes: C2H4 (g) + HOBr (aq) -------------------> HO-CH2-CH2Br (aq) Still, the brownish - reddish colour of the bromine water will decolourise. This is a useful way of distinguishing between alkanes and alkenes of similar molecular weights. ***RS**
yes there are 3 isomers. CHBr=CHBr, HCBr=HCBr, BrCBr=CH2(double bonded CH2 onto the C as well
Well the question itself is very wide. Bromine is number 35, member of 4th period and 17th group. It is a non metal. It is a halogen, only liquid halogens of all. It has 4 electron layers [as you can see from period number] and 7 electrons in outer layer [as you can see from old fashioned element tables, where it is in 7a group] It is less reactive than other similar substances Chlorine and Florine, however, it is more reactive than Iodide. It can react with hydrogen and form a Bromine acid. Bromine is widely used in organic chemistry, where bromine water is used to recognize any material [except benzene] which has double or triple connections, because it breaks double connection and attach itself. Reaction looks like CH2 = CH2 +Br2 -> CH2BR - CH2Br
by removal of hydrogen molecule one more pi bond will be formed between carbons thus ethene will convert in ethyneEdit by some other dude named Timaeus:Yeah...no. That's not right at all. This is how it's done:First, halogenation of ethene to form a vicinal dihalide. Then a second order elimination reaction, let's say using a bulky nucleophile like tert-butoxide, to convert it to a bromoethene. Then just once more with the E2 reaction to form ethyne.
Electron affinity is that energy released when one electron is added to a gaseous atom of an element. For MgMg(g) + e- -> Mg- (g) ; Energy = 0 kJ/molIt is different from ionization potential which is the energy required to remove one electronMg(g)-> Mg+(g)+2e-