0
You can't really take that power, but you can take the limit - meaning you can see what happens when the exponent gets closer and closer to "minus infinite". That limit is zero.
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What is e raised to the 0th power?
e raised to the 0 power is 1
What is the first derivative of e raised to the power of x?
The first derivative of e to the x power is e to the power of x.
What is a million raised to the ninth power?
1.e+54
What is the square root of e when x over y equals various or variable may be known as 2x minus y to the power of e?
matter equels y to the power x plus e
How do you integrate of e power 2x plus e power minus 2x?
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
What is e raised to the 0th power?
e raised to the 0 power is 1
What is the first derivative of e raised to the power of x?
The first derivative of e to the x power is e to the power of x.
E raised to the power of x equal 10?
It is possible.
What is a million raised to the ninth power?
1.e+54
What is e to the power minus infinity?
that would be the inverse of e to the plus infinity Answer is thus zero
What is value of iota raise to the power iota raise to the power iota till infinity?
the answer is e raise to power minus pi/2
What is the square root of e when x over y equals various or variable may be known as 2x minus y to the power of e?
matter equels y to the power x plus e
How can you prove that yis equal to e raise to the power xlny?
Euler's constant, e, has some basic rules when used in conjunction with logs. e raised to x?æln(y),?æby rule is equal to (e raised to ln(y) raised to x). e raised to ln (y) is equal to just y. Thus it becomes equal to y when x = 1 or 0.
How do you integrate of e power 2x plus e power minus 2x?
int[e(2X) +e(- 2X)] integrate term by term 1/22 e(2X) - 1/22 e(- 2X) + C (1/4)e(2X) - (1/4)e(- 2X) + C ====================
How do you factor e raised to 2x -1 divided by e raised to x minus 1?
This question involves a property of dividing common bases. For example, xm/xn is the same as saying x(m-n). Whenever two common bases are being divided, the exponents can be combined by subtraction. So, for this problem: e(2x-1)/e(x-1), the e can be written once, with the exponents being subtracted: e2x-1-(x-1), distributing the minus sign arrives at e2x-1-x+1, or ex. ANS: ex
Why e raise to -t is greater than or equal to 0?
A positive number, raised to any power, is positive.
Simplify the expression 5 e raised to the x power divided by 6 e?
0.8333
