Hydrogen Bromine Oxygen4
Mercury (I) bromite
HgBr2
Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat
Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat
It is HgBr2.
HgBr2
Mercury(II) bromide
Mercury (II) Bromide
HgBr2 is mercury II bromide or mercuric bromide.
Mercury(I) bromide formula is Hg2Br2Mercury(II) bromide formula is HgBr2See attached link for more information on mercury bromide.
+1 is the oxidation state of Hg in Hg2CI2.
To answer you question HgBr2 is soluble in water. I had the same question so I surfed around a bit and found the answer on a chemistry based website talking about solublity and net ionic equations. Hope this helps~
likely it would form the +2 ion (the mercury), so put the Hg in brackets, with a +2 charge at the top right corner out side the bracket. put a bromine, with 8 electrons, in a bracket, with a -1 charge at its top right outside the bracket, and then do it again. formula has to be HgBr2. if it's the Hg+1 ion, do the same as I just wrote, but only include one bromine ion