Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat
HgBr2
Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat
HgBr2
It is HgBr2.
The dissociation equation for mercury(II) bromide (HgBr2) in water is: HgBr2(s) -> Hg2+(aq) + 2Br-(aq)
Mercury (II) Bromide
HgBr2 is mercury II bromide or mercuric bromide.
Mercury(II) bromide
+1 is the oxidation state of Hg in Hg2CI2.
First, balance the chemical equation: Hg + Br2 → HgBr2. Calculate the molar amount of each reactant using their respective molar masses. Identify the limiting reactant (the one that produces the least amount of product). Calculate the theoretical yield of HgBr2 based on the limiting reactant.
Mercury(I) bromide formula is Hg2Br2Mercury(II) bromide formula is HgBr2See attached link for more information on mercury bromide.