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Take the FW weight of the HgBr2-360.398g/mol
divide it by the atomic weight of Mercury=200.59g/mol
1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898g

To make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of water

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Isaac Kiplagat

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How do you make a 1000ppm mercury solution from solid reagent mercury bromide-HgBr2 FW360.398?

Take the FW weight of the HgBr2-360.398g/moldivide it by the atomic weight of Mercury=200.59g/mol1g Hg in relation to FW of HgBr2 = 360.398/200.59 = 1.7966898gTo make 1000ppm of Hg, dissolve 1.79669g of HgBr2 in 1000ml of waterGet in touch if you are stuckIsaac Kiplagat


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