From Generation to Generation was created in 1959.
gametophyte generation
It will be 1/9 as intense (or badly phrased, "nine times lower").Intensity is defined as the energy crossing per unit area in unit time. So intensity will be inversely proportional to the square of the distance.So as distance is multiplied by 3 times then intensity would be reduced by 3² i.e. 9 times.(A meter reveals that the sound level has dropped by 9.54 dB.)For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance. I2 = I1 * (r1/r2)² I2 = I1 * (1/3)² = (I/ 9)*Do not forget that the sound pressure is not the same as sound intensity. Sound pressure needs the distance law 1/r. (No square at all).For sound pressure we use in the free field (direct field) the inverse distance law = 1/r. p1 and r1 belong to the close distance and p2 and p2 belong to the far distance.p2 = p1 x r1/r2p2 = p1 x 1/3 = p1 / 3Three times farther away gives one third the sound pressure of the close sound pressure.For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 x (r1/r2)²I2 = I1 x (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.Scroll down to related links and look at "Sound pressure p and the inverse distance law 1/r".For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.Do not forget that the sound pressure is not the same as sound intensity. Sound pressure needs the distance law 1/r. (No square at all).For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 x (r1/r2)²I2 = I1 x (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.For sound pressure we use in the free field (direct field) the inverse distance law = 1/r. p1 and r1 belong to the close distance and p2 and p2 belong to the far distance.p2 = p1 x r1/r2p2 = p1x 1/3 = p1 / 3Three times farther away gives one third the sound pressure of the close sound pressure.Scroll down to related links and look at "Sound pressure p and the inverse distance law 1/r".For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 x (r1/r2)²I2 = I1 x (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.For sound pressure we use in the free field (direct field) the inverse distance law = 1/r. p1 and r1 belong to the close distance and p2 and p2 belong to the far distance.p2 = p1 x r1/r2p2 = p1 x 1/3 = p1 / 3Three times farther away gives one third the sound pressure of the close sound pressure.Scroll down to related links and look at "Sound pressure p and the inverse distance law 1/r".For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.For sound pressure we use in the free field (direct field) the inverse distance law = 1/r. p1 and r1 belong to the close distance and p2 and p2 belong to the far distance.p2 = p1 * r1/r2p2 = p1 * 1/3 = p1 / 3Three times farther away gives one third the sound pressure of the close sound pressure.Scroll down to related links and look at "Sound pressure p and the inverse distance law 1/r".
F1 Generation
how traits are PASSED from generation to generation.
Ellipses (...) used to emulate indentation... swap (int *i1, int *i2) { /* only works for integers, i1 != i2 */ ... *i1 = *i1 ^ *i2; ... *i2 = *i1 ^ *i2; ... *i1 = *i1 ^ *i2; }
The powers of i are: i1 = i i2 = -1 i1 = -i i1 = 1 After that, the pattern repeats, so i6 = -1.
When "n" number of varying resistances are connected in series R total = R1+R2+R3+R4+ . . . . . = Req V total = (V1* I1)+(V2* I1)+(V3* I1)+(V4* I1) { As I1=I2=I3=I4} V total = V battery I total = V battery / Req = I1=I2=I3=I4= . . . . . = Ieq
firstly take the reference of i1 then through i1 we can follow up to the end
To find the next permutation of an array ar:Find the highest index, i1 such that ar[i1] is the first of a pair of elements in ascending order. If there isn't one, the sequence is the highest permutation, so reverse the whole thing to begin again.Find the highest index i2, such that i2 > i1 and ar[i2] > ar[i1].Swap ar[i1] and ar[i2].The elements from ar[i1 + 1] to the end are now in descending order (a later permutation), so reverse them.
These are the two functions you need: public static int lcm(int i1, int i2) { return (i1*i2/gcd(i1,i2)); } public static int gcd(int i1, int i2) { // using Euclid's algorithm int a=i1, b=i2, temp; while (b!=0) { temp=b; b=a%temp; a=temp; } return a; }
i1 billion
Assume that the two inputs of the XOR gate are I1 and I2, and that the two inputs of the multiplexer are M1 and M2 and the selection line is S: Connect I1 to M1 Connect Not(I1) to M2 Connect I2 to S
39.37 inches
It's (I1./I2*)/(|I1./I2*|), where I2* is the complex conjugate of the Fourier transformed Image 2
It gets confusing with the number 1. I1
I forgot my password