Kb=[HCn][OH-]
[CN-]
The Kb for CN- (aq) is the equilibrium constant for the reaction of CN- with water to form HCN (aq) and OH- (aq). It represents the strength of the base CN- in solution. It can be calculated by taking the concentration of the products (HCN and OH-) and dividing by the concentration of CN- at equilibrium.
Kb=[HCN][OH-]/[CN-]
The Kb value for CH3NH2(aq) is 4.4 x 10^-4.
Kb=[(Ch3)3 NH+][OH-] __________ [(Ch3)3 N]
kb=[C5H5NH+][OH-]______[C5H5N]
ka=[H+][CN-]/[HCN]
Kb=[HCN][OH-]/[CN-]
The Lewis dot structure of HCN (hydrogen cyanide) has the hydrogen atom bonded to the carbon atom with a single bond and the carbon atom bonded to the nitrogen atom with a triple bond. Each atom has a full valence shell, with hydrogen having 2 valence electrons, carbon having 8 valence electrons, and nitrogen having 8 valence electrons.
The Kb for C5H5N (pyridine) is 1.7 x 10^-9. This value indicates the strength of the base in solution, with lower values suggesting a weaker base and higher values indicating a stronger base.
The Kb value for CH3NH2(aq) is 4.4 x 10^-4.
kb=[C5H5NH+][OH-]______[C5H5N]
Kb=c5h5nh+oh- / c5h5n (apex.)
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
The Kb for (CH3)3N (trimethylamine) in water is a measure of the strength of the base (CH3)3NH in solution. It is used to calculate the equilibrium concentration of hydroxide ions (OH-) in solution when the base dissociates.
Kb=[(Ch3)3 NH+][OH-] __________ [(Ch3)3 N]
ka=[H+][CN-]/[HCN]
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
HCl + KOH → KCl + H2O Hydrochloric acid (HCl) reacts with potassium hydroxide (KOH) to form potassium chloride (KCl) and water (H2O) in a neutralization reaction.