Want this question answered?
Na+H2o+H2=2 Nhoh
This is the iodhydric acid.
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
This is the a change of phase from liquid to gas.
kb=[C5H5NH+][OH-]/[C5H5N]
kb=[C5H5NH+][OH-]______[C5H5N]
Kb=c5h5nh+oh- / c5h5n (apex.)
KBr + H2O = Kaq+ Braq- Haq+ OHaq-
NaS plus H2O
c2h5oh+h2o
No they are not the products.Product is as this. H2SO3
3NO2 + H2o = 2HNO3 + NO
CuO + 2HCL - CuCl2 + H2O
No. The correct one is CO + H2O ----> HCOOH (Formic acid)
XeF4+H2O->XeO3+HF+H2O
Na+H2o+H2=2 Nhoh