170 km taking this route:EXIT the airport, and follow signs to N17 GALWAY.Take N17 to N18 LIMERICK in Claregalway.Take N18 to Limerick.
About 89 miles on N17 & N18
748 High Rd, Tottenham, London N17 0AP, United Kingdom
Gish s gs g s gs g s gs g s gs g s g
You need sand and gunpowder, crafted like this: S G S G S G S G S S = Sand G = Gunpowder
I believe 170 Degree Thermostat is pretty much basic.
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
The answer is NOT a)a) I(g) + e → I-(g)b) I2(g) → 2I(g)c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)
a) I(g) + e → I-(g)b) I2(g) → 2I(g) c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)The correct answer out of these choices is clearly a) I(g) + e → I-(g). That is the right answer.
Unfortunately, you did not specify what final chemical equation you wanted given these formulas. From the data though I assumed the following: Fe2O3(s) + 3CO(g) à 2Fe(s) + 3CO2 H1 3Fe2O3(s) + CO(g) à 2Fe3O4(s) + CO2(g) H2 Fe3O4(s) + CO(g) à 3FeO(s) + CO2(g) H3 3(Fe2O3(s) + 3CO(g) à 2Fe(s) + 3CO2) 3(H1) 2Fe3O4(s) + CO2(g) à3Fe2O3(s) + CO(g) -H2 2(3FeO(s) + CO2(g) à Fe3O4(s) + CO(g)) 2(-H3) 3Fe2O3(s) + 9 (6)CO(g) à 6Fe(s) + 9(6)CO2 3(H1) 2Fe3O4(s) + CO2(g) à3Fe2O3(s) + CO(g) -H2 6FeO(s) + 2CO2(g) à 2Fe3O4(s) + 2CO(g) 2(-H3) 6FeO(s) + 6CO(g) à 6Fe(s) + 6CO2 3H1 + -H2 + -2H3 FeO(s) + CO(g) à Fe(s) + CO2 [(3H1 + -H2 + -2H3) / 6] FeO(s) + CO(g) à Fe(s) + CO2 -11KJ/mol
here is its s s s * - S P ( - P O [%P] P O s Y i 4 - s s s s s s s * S P ( - P O [%P] P P s O [4o] i - * * * * ( ( ( ( % % % % 4 4 4 4 - s s s s * - S P ( - P O [%P] P O P P s O [4o] i - s s s s s * - S P ( - O O s P O O s P O O g g g g g * - s D ( - D D [%D] D D S - [4s] s s s s s s s s* - S P ( - O O s P O O s P O O - O g g g D g D ( - P s S - [%D] D D s D s 4 - i o O - g g g D g D ( - P s S S D s D D s D s 4 i o O - g g g D g h ( H h - D D D D S S s - s s s s * - S P ( - O P O o o s o O 4Share this:
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