NH4 is an ammonium cation (positively-charged molecular version of ammonia NH3) and it would look like this:
H
H N H
H
(NH4)2SO4 --> 2 (NH4)+ and (SO4)2- In words: 2 ions of ammonium and 1 ion of sulfate
It would be ammonium phosphide.
Yes, look at this: ammonia is a very weak base, partially ionising in water:NH3 + H2O
To determine the number of grams in 2.80 moles of (NH4)2SO3, you need to multiply the molar mass of (NH4)2SO3 by the number of moles. The molar mass of (NH4)2SO3 is 132.14 g/mol, so 2.80 moles of (NH4)2SO3 would be equal to 2.80 moles x 132.14 g/mol = 369.392 grams of (NH4)2SO3.
"NH4" I assume is NH4+This is the ammonium ion.
[NH4]+ is ammonium for the ion. For the uncharged molecule it would be nitrogen tetrahydride NH3 is ammonia or nitrogen trihydride
NH3Cr2o7 is ammonium dichromate and CoCl3 is cobalt III Chloride
NH4 is colorless.
The compound is ammonium oxide. You can tell because the NH4+ and O2- ions are present.
NH4 is the chemical formula of the cation ammonium - (NH4)+.
The chemical formula of ammonium sulphite is (NH4)2SO3.
The formula for Ammonium Phosphite is (NH4)3 PO3.