The products in the reaction of Zn(NO3)2 with 2 NaOH are Zn(OH)2(s) and 2 NaNO3 . There are no 'elements' involved
Zn(OH)2 (zinc hydroxide) is formed
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
NaOH + NH4Cl --> NH3 + H2O + NaCl The products are ammonia, water, and sodium chloride.
Zn is a semi metal and reacts with acid as well as with alkali. Zn + 2NaOH ---------> Na2ZnO2 + H2
The products in the reaction of Zn(NO3)2 with 2 NaOH are Zn(OH)2(s) and 2 NaNO3 . There are no 'elements' involved
Zn(OH)2 (zinc hydroxide) is formed
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
There's two possible reactions Zink with solid NaOH gives double salt Zn + 2NaOH --t--> Na2ZnO2 + H2 And I Think you need the other one: Zink with NaOH(aq) gives the complex salt: Zn + 2NaOH + 2H2O --> Na2[Zn(OH)4] + H2
NaOH + NH4Cl --> NH3 + H2O + NaCl The products are ammonia, water, and sodium chloride.
Zn is a semi metal and reacts with acid as well as with alkali. Zn + 2NaOH ---------> Na2ZnO2 + H2
intially: Zn2+ + 2OH- -->Zn(OH)2 excess hydroxide: Zn(OH)2 + 2OH- --> [Zn(OH)4]2- It is true that excess hydroxide reacts further, but the reaction is as under: Zn(OH)2 +2(OH)- ----> (ZnO2) 2- +2H2O or ZnSO4 + 4NaOH ------> 2Na2ZnO2 +2H2O, the white precipitate of zinc hydroxide dissolves with excess hydroxide and forms a soluble complex called sodium zincate. The solution becomes clear. No ppt.
Zn + CuBr2 = Cu + ZnBr2
Aluminium hydroxide = Al(OH)3 , and Zinc hydroxide = Zn(OH)2 , is redissolved in excess Sodium hydroxide = NaOH (in water solution) : Al(OH)3 + NaOH + H2O ----> NaAl(OH)4 Zn(OH)2 + NaOH + H2O ----> Na2Zn(OH)4
Zn(NO3)2+ NiO
Simple methods:- reaction of Zn with HCl- reaction of Al with NaOH
No. Zn + 2HCl = ZnCl2 + H2