If no other forces (such as friction) act on an object, or if friction is insignificant (such as, when a heavy object just begins to fall), the acceleration is 9.8 meters per second square. This means that every second, the speed will increase by 9.8 meters per second.
Weight = mass x g ... the gravitational acceleration at the earth's surface. Fwt = mg = 3.5 x 9.8 = 34.3 n
Strictly speaking its not the same . This equation calculates the acceleration: acceleration = ( G * ( m1 + m2 ) ) / d2 where: G = newtons gravity constant m1 = earths mass (kg) m2 = objects mass (kg) d = distance between centres of gravity (metres) The earths mass is so large however, only a significantly large object mass would make a real difference to the acceleration.
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
The Earth's gravitational field and gravitational potential energy are really two quite different things. The relationalship is the following: Gravitational potential energy = mass x gravity x height Where gravity is the acceleration due to gravity - near Earth's surface, that's 9.8 meters/second2 - or the equivalent, weight per unit mass (which near Earth's surface is 9.8 newton/kilogram).
Yes, exactly. Free fall results in constant acceleration.
The biggest influence on Earths tides comes from the gravitational effects from the Moon.
Because the Earths' mass demands it be so.
Force (newtons) = mass (kg) * acceleration (m/s/s) > Acceleration at earths surface radius = 9.82 m/s/s
Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s
Weight = mass x g ... the gravitational acceleration at the earth's surface. Fwt = mg = 3.5 x 9.8 = 34.3 n
The mean acceleration rate due to gravity on the Earth is 9.81 meters per second squared ( 9.81 m/s^2 ) or 32.17 feet per second squared ( 32.17 ft/s^2 ).
When you get out of earths gravitational pull, you aren't rotating around it like the moon. You are free to float into space.
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
A small or lower case g g = approximately 9.81 metres per second squared, or metres per secon, per second.
That would have to be at a radius that is sqrt(26) = 5.1 times the Earth's physical radius, or about 32,486 kilometers (20,186 miles) from the center.
Strictly speaking its not the same . This equation calculates the acceleration: acceleration = ( G * ( m1 + m2 ) ) / d2 where: G = newtons gravity constant m1 = earths mass (kg) m2 = objects mass (kg) d = distance between centres of gravity (metres) The earths mass is so large however, only a significantly large object mass would make a real difference to the acceleration.
I believe your answer would be gravity. You are always being pulled by the Earths gravitational force, and it is what keeps your feet on the ground, and fall down if you are not conected to something.