0
What is the distance from the Earths center to a point outside the Earth where the gravitational acceleration due to the Earth is 1 26 of its value at the Earths surface?
Wiki User
∙ 10y ago
That would have to be at a radius that is sqrt(26) = 5.1 times the Earth's
physical radius, or about 32,486 kilometers (20,186 miles) from the center.
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What is the planet earth's gravitational force?
This can be measured by the acceleration due to gravity at the surface. Earth's surface gravitational acceleration is about 9.8 m/s2
Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
What is the gravitational acceleration of an object on the surface of the earth?
At or near the surface of the earth, the acceleration due to gravity is 32 feet per second per second
How do you find the weight of an object on earth?
You could weigh it against other objects. If it is not on the surface, multiply its mass by the acceleration of gravity (at that distance) to find its gravitational potential in newtons.
Why does a man get hurt when he jumps from a significant height even though newtons universal gravitational law says that height is inversely proportional to acceleration due to gravity?
The difference in gravitational acceleration depends on the distance from the centre of the earth , not the surface. The equation for the new rate of accelration calculated from the surface rate is: > a = k / ( ( d / r )2 ) > where: a = acceleration due to gravity at new position k = surface rate of acceleration ( use 9.82 (m/s)/s ) d = distance from earths centre to new position ( r + height of jump) ( 6376000 metres) r = surface radius ( use 6371000 metres ) > Even if you jump from 5,000 metres the rate of acceleration would be : > 9.8046 (m/s)/s , which is 99.84 % of the rate at the surface
Where do you experience more gravity on earths surface or earths center?
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
What is the force of gravity on a person or object on the surface of a planet?
The force of gravity on a person or object at the surface of a planet is calculated by the product of the mass of the person or object and the gravitational constant acceleration for the planet. For Earth, the gravitational acceleration is 9.8 m / s^2.
How do you overcome the factor of gravitational acceleration?
By increasing the surface area so that air resistance increases
What is the earth's gravitational constant?
At the Earth's surface, the acceleration due to gravity is 9.8 m/s2.
How does surface tension depend on surface area?
I think its depends on the nature of the liquid, the surrounding environment like (Gravitational acceleration ) and temperature
Why is the acceleration on earth different on mars?
The gravitational force between two masses depends on the product of their masses and the distance between their centers. The gravitational acceleration on a planet depends on the planet's mass and the distance of its surface from its center. So if two planets have different masses or different sizes, then you'd naturally expect their gravitational accelerations to be different. No two planets or moons in the solar system have the same mass or the same size, so no two of them have the same gravitational acceleration. Compared to Earth, it's 62% less on Mars, 83% less on the Moon, 10% less on Venus, and 164% more on Jupiter.
What is the field strength at a distance one Earth radius beyond the surface?
I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.I assume you mean, of the gravitational field? The gravitational field is inversely proportional to the square of the distance. At a distance of 1 Earth radius, the distance from the center of the Earth is twice the distance at the Earth's surface; thus, the field strength is 1/4 what it is on the surface. If at the surface the field strength is about 9.8 meters per second square, divide that by 4 to get the field strength at a distance of one Earth radius from the surface.
