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One number is 8 more than twice the second number The sum of the numbers is 123 Find the numbers?
Let a be the first number and b the second number then, (1) a = 8 + 2b and (2) a + b =123 From (2) a = 123 - b substituting for a in (1) gives :- 123 - b = 8 + 2b , 3b = 115, b = 115/3 = 38⅓. and substituting for this in (2) gives :- a + 38⅓ = 123, a = 123 - 38⅓ = 84⅔. So, a = 84⅔ and b = 38⅓
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