IR drop across a resistance is voltage.
The letter I means current, and the letter R means resistance. Current times resistance, by Ohm's law is voltage.
IR Drop means voltage drop. As voltage drop across any resistance is product of current (I) passing through resistance and resistance value(R ) , it is often written as IR drop.
V=IR by ohms law. Voltage across the resistor is the product of current flowing and resistance of the conductor at constant temperature.
A: There are tables that qualify IR drops for wire lenght. All wire do offer resistance to current this current will cause directly a volatge drop according to the wire resistance so it can be measured to find the IR drop
Voltage drop across a circuit is IZ, where I is current and Z is impedance. In other words IZ = IR + jIX, where R is resistance and X is inductance
as the resistance/impedance of the the conducting wire is so small as compared to the load, there is a very low voltage drop across the conducting wires. keep the Ohm's law in mind i.e. V=IR <><><> Agree- but making the conducting wires LONG enough, and there will be enough resistance for a voltage drop.
In Ohm's Law, E stands for voltage, I stands for current (amps), and R stands for resistance. Ohm's Law states: E = IR or voltage equals current times resistance. This means that current flowing through a wire (that has resistance) produces a voltage drop in the wire. Since the voltage drop is the result of current flowing through a resistance, old-school engineers will sometimes refer to it as "IR drop". So, since E = IR, saying "IR" is the same as saying "voltage".
In a series circuit, the voltage drop across each resistor is proportional to its resistance value according to Ohm's Law (V = IR). The total voltage supplied by the source is divided among the resistors, so the sum of the individual voltage drops equals the total voltage. As a result, resistors with higher resistance will have a larger voltage drop compared to those with lower resistance.
Yes
Resistance is decreases then the voltage drop across it is decreases because of ohms law (V=IR),due to this power can also be decreases because of P=VI. so finally we can say that resistance decreases ,power also decreases.
Using ohm's law, V=IR then R=V/I =6/0.0015=4000 ohm = 4k ohm resistor.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
In a series circuit, the total voltage supplied by the source is divided among the resistors based on their resistance values. According to Ohm's Law (V = IR), a resistor with a larger resistance will have a larger voltage drop when the same current flows through it. Therefore, the resistor with the highest resistance in a series circuit will indeed experience the largest voltage drop. This is because the voltage drop across each resistor is directly proportional to its resistance.