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What is a crossove?

Updated: 12/11/2022
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14y ago

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A crossover is when you take to things together and make a new story, for example:

say I take sky high and Spider-Man and make a story about a girl named April Parker.

She just got her powers and her parents want her to go to sky high to learn how to control them. As soon as she to the school she makes new friends. And some meets some bullies, but soon one of the bullies falls in love with her.

And that's basically what a crossover is.

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14y ago
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11y ago

when you get rocked by a person with handles (demario merrick got handles he can rock ay body)

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Q: What is a crossove?
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C program to for traveling salesman problem?

#include<conio.h> #include<stdio.h> #include<stdlib.h> #define N 50 //Travelling sales man problem , travelling between 6 cities. //initializing the path lengths between cities and the paths to be included //in population void initialize(int pathlen[][6],int path[][6]) { int i,j,k; //obtaining pathlengths for(i=0;i<6;i++) { for(j=0;j<6;j++) { if(j<i) //path length from a to b will be same as b to a { pathlen[i][j]=pathlen[j][i]; } if(j==i) // path length from a to a will be 0 { pathlen[i][j]=0; } if(j>i) // rest initialized { do{ pathlen[i][j]= random(20); }while(!pathlen[i][j]); } } } // display the path lengths printf("\n\tThe PATH LENGTHS ARE: \n" ); for(i=0;i<6;i++) { for(j=0;j<6;j++) { printf(" %5d ",pathlen[i][j]); } printf("\n\n"); } // generating the population for(i=0;i<20;i++) { for(j=0;j<6;j++) { path[i][j]=random(6); for(k=j-1;k>=0;k--) { if(path[i][j]==path[i][k]) //checking to avoid repeatition { path[i][j] = random(6); k=j; } } } } } // evaluating the fitness function or total distance void evaluate(int pathlen[6][6],int path[20][6],int fx[20]) { int sum =0,i,j,a,b; //obtaing the sum of the path taken for(i=0;i<20;i++) { sum=0; for(j=0;j<5;j++) { a=path[i][j]; b=path[i][j+1]; sum=sum+pathlen[a][b]; } fx[i]=sum; } //display the paths generated printf("\n"); printf("\n\tPATH \t\tf(x) \n\n"); for(i=0;i<20;i++) { printf("\t"); for(j=0;j<6;j++) { printf(" %d",path[i][j]); } printf("\t%d",fx[i]); printf("\n"); } } //selecting the two points for cross over and then performing partial Crossover void selection(int fx[20],int pos[2],int posmax[2]) { int min1=fx[0],min2=fx[0],i,max1=fx[0],max2=fx[0]; pos[0]=0; pos[1]=0; posmax[0]=0; posmax[1]=0; //calculating the minimum postion for(i=1;i<20;i++) { if(fx[i]<min1) { min1=fx[i]; pos[0]=i; } } //calaculating the second minimum position for(i=1;i<20;i++) { if(fx[i]<min2&&i!=pos[0]) { min2=fx[i]; pos[1]=i; } } //calculating the max position for(i=1;i<20;i++) { if(fx[i]>max1) { max1=fx[i]; posmax[0]=i; } } //calculating the second max position for(i=1;i<20;i++) { if(fx[i]>max2&&i!=posmax[0]) { max2=fx[i]; posmax[1]=i; } } printf("\n\tFIRST MINIMUM=%4d \tPOSITION=%4d\n\tSECOND MINIMUN=%4d \tPOSITION=%4d\n\tFIRST MAXIMUM=%4d \tPOSITION=%4d\n\tSECOND MAXIMUM=%4d \tPOSITION=%4d\n",min1,pos[0],min2,pos[1],max1,posmax[0],max2,posmax[1]); } //PERFORMING PARTIAL CROSSOVER void crossover(int pos[2],int path[][6],int child[2][6]) { int crosspt1,crosspt2,j,i,temp,temp1[2][6],temp2; //TAKING 2 CROSS POINTS do { crosspt1=random(5); }while(crosspt1>2) ; do { crosspt2=random(5); }while(crosspt2<=3); clrscr(); printf("\n\n\t The CROSSOVER POINTS ARE : %d , %d ",crosspt1,crosspt2); printf("\n\n\tTHE PATHS FOR CROSSOVER ARE"); printf("\n\n\t\t"); for(j=0;j<6;j++) { child[0][j]=path[pos[0]][j]; printf(" %d",child[0][j]); } printf("\n\t\t"); for(j=0;j<6;j++) { child[1][j]=path[pos[1]][j]; printf(" %d",child[1][j]); } int cnt=0; //swapping the paths between two crosspoints for(j=crosspt1+1;j<=crosspt2;j++) { temp1[1][cnt]=child[0][j]; temp1[0][cnt]=child[1][j]; temp=child[0][j]; child[0][j]=child[1][j]; child[1][j]=temp; cnt++; } //performing partial crossover int k,m; for(m=0;m<2;m++) { for(i=0;i<crosspt1+1;i++) //taking the path before crosspoint { for(j=0;j<cnt;j++) //comparing the path within crossover point { if(child[m][i]==temp1[m][j]) //if found then { if(m==0) //for child 1 { temp2=temp1[1][j]; //take the path from child2 crossover for(k=0;k<6;k++) { if(child[m][k]==temp2) //if still the path repeats then repeat the process again { temp2=child[1][k]; k=0; } } child[m][i]=temp2; //finally putting the value in child } else //for child 2 { temp2=temp1[0][j]; for(k=0;k<6;k++) { if(child[m][k]==temp2) {temp2=child[0][k]; k=0; } } child[m][i]=temp2; } } } } } for(m=0;m<2;m++) { for(i=crosspt2+1;i<6;i++) //now chehcking the path after the second cross point { for(j=0;j<cnt;j++) //comparing the path within crossover point { if(child[m][i]==temp1[m][j]) //if found then { if(m==0) //for child 1 { temp2=temp1[1][j]; //take the path from child2 crossove for(k=0;k<6;k++) { if(child[m][k]==temp2) //if still the path repeats then repeat the process again {temp2=child[1][k]; k=0; } } child[m][i]=temp2; //finally assigning the value } else //for child 2 { temp2=temp1[0][j]; for(k=0;k<cnt;k++) { if(child[m][k]==temp2) {temp2=child[0][k]; k=0; } } child[m][i]=temp2; } } } } } //display AfTER CROSSOVER printf("\n\tAFTER CROSSOVER\n\t\t"); for(j=0;j<6;j++) { printf(" %d",child[0][j]); } printf("\n\t\t"); for(j=0;j<6;j++) { printf(" %d",child[1][j]); } } //insering the paths in population removing those having maximum populaiton void insert(int child[2][6],int posmax[2],int path[20][6]) { for(int j=0;j<6;j++) { path[posmax[0]][j]=child[0][j]; path[posmax[1]][j]=child[1][j]; } } // performing mutation void mutation(int child[2][6]) { int sel=random(2); int pos1=random(6); int pos2=random(6); int temp=child[sel][pos1]; child[sel][pos1]=child[sel][pos2]; child[sel][pos2]=temp; } void main() { clrscr(); randomize(); int pathlen[6][6],path[20][6],fx[20],pos[2],posmax[2],child[2][6]; printf("\n\t\t\t TRAVELLING SALESMAN PROBLEM "); printf("\n\t\t\t_____________________________"); printf("\n\n\n\t\tTHE TRAVELLING SALES MAN PROBLEM DEALS WITH THE FACT"); printf("\n\n\t\tTHAT A SALESMAN TRAVELS BETWEEN CITIES TAKING THE PATH"); printf("\n\n\t\tTHAT IS OF MINIMUN DISTANCE."); printf("\n\n\n\t\tTO OBTAIN THE MINIMUM DISTANCE WE USE GENETIC ALGO"); printf("\n\n\t\tWHERE WE TAKE AN INITIAL POPULATION OF 20 PATHS AND "); printf("\n\n\t\tAND THEN THROUGH FITNESS FUNCTION WE OBTAIN THE PATHS "); printf("\n\n\t\tWITH MINIMUN DISTANCE AND REPLACE THEM WITH THE CHILDS "); printf("\n\n\t\tAFTER PARTIAL CROSSOVER WITH MAXIMUM DISTANCE."); getch(); clrscr(); initialize(pathlen,path); evaluate(pathlen,path,fx); getch(); selection(fx,pos,posmax); crossover(pos,path,child); mutation(child); getch(); insert(child,posmax,path); for(int i=1;i<N;i++) { evaluate(pathlen,path,fx); selection(fx,pos,posmax); crossover(pos,path,child); mutation(child); insert(child,posmax,path); } evaluate(pathlen,path,fx); selection(fx,pos,posmax); crossover(pos,path,child); insert(child,posmax,path); evaluate(pathlen,path,fx); getch(); }