A restriction enzyme.
what are the mai sequence of stars
i think that order of importance is a list of important sequece in importance value
basically its function is to initiate the sequece of micro-operations to be performeed on the data stored in registers in computer.
The Fibonacci sequence starts with the numbers 0 and 1 (or 1 and 1 - there are slightly different definitions). After that, each number is the sum of the previous two numbers.
Most of its active life, usually. The actual time may vary from only a few million years (for very massive stars) to trillions of years (for some red dwarves).
The correct complimentary DNA sequence would be AGTCCTGGC. The correct complimentary mRNA sequence would be AGUCCUGGC.
Stars spend most of their life in the main sequence phase, where nuclear fusion of hydrogen into helium occurs in their cores, producing energy that counteracts gravitational collapse. This phase can last billions of years for stars like our Sun.
operon is a group of genes regulated by a single promoter and operator. . . generally all the genes (structural genes of a particular operon) regulate a specific metabolic pathway. . (eg : lac operon in bacteria; where 3 genes are regulated by a single promoter sequece which help in the catabolism of lactose). . . if you have any doubts mail me at vegi.chaitanya@gmial.com
The restriction enzymes have ability to cut on a specific sequences that are knwon as palandreomic sequences now they cut in two way i.e. blunt and sticky for e.g. if we have a sequece of ATTCGTAAGC it will be cutted in two way as ...................................................TAAGCATTCG 1. ATTCG......... TAAGC i.e., blunt or straight form all ends ....TAAGC .........ATTCG 2. ATT .................CGTAAGC ....TAAGCAT .................TCG i.e., sticky or uneven ends The reason for this phenomena is still not clear or knwon
t(n) = 5 6 8 11 15 First differences = 1 2 3 4 Second differences = 1 1 1 So the sequence is quadratic with the coefficient of n2 being half of the second difference ie half of 1. So t(1) = 0.5*12 + b*1 + c = 5 ie b + c = 4.5 and So t(2) = 0.5*22 + b*2 + c = 6 ie 2b + c = 4 Solving these two equations simultaneously, b = -0.5 and c = 5 Therefore, the sequence is t(n) = (n2 - n + 10)/2
The most massive star (The star with the most mass) is a star in a super star cluster called R136 or RMC 136 in the Large Magellanic Cloud (LMC). [See related link for more information] The star, for all its fame has a rather unremarkable name of R136a1. It has the mass of about 265 -> 300 solar masses (256 x the mass of the Sun - See related question). See related link [BBC] for a pictorial size comparison. It is a blue supergiant with a spectral type of O3. Because of its mass and intense luminosity (10 million times that of our own Sun) it, astronomically, will have a very short lifetime in the millions of years rather than billions. At the end of its life, R136a1 will explode as a supernova and because of its relatively close distance to Earth (165,000 light years/ALU [See related question] it might be visible during the day. This question is about the most massive star (mass), not the largest (Radius) [See related question]