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What is a node?

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Answered 2010-05-07 09:30:55

its an intersection point; where things meet
A node (knot) is a point along a standing wave where the wave has minimal amplitude. The opposite of a node is an antinode, a point where the amplitude of the standing wave is a maximum. These occur midway between the nodes

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Write an iterative function to search an element in a binary search tree?

_node* search (_node* head, _key key) { _node* node; for (node=head; node != NULL;;) { if (key == node->key) return node; else if (key < node.>key) node = node->left; else node = node->right; } return node; }

How to find the mirror image of a binary tree?

Refer to void mirror(struct node* node) { if (node==NULL) { return; } else { struct node* temp; // do the subtrees mirror(node->left); mirror(node->right); // swap the pointers in this node temp = node->left; node->left = node->right; node->right = temp; } }

How to Print data of all nodes of linked list?

for (node=head; node!=null; node=node->next) printnode(node);

Is null node equal to leaf node?

No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.

How do you insert a node into a doubly linked list?

To insert a node into a doubly linked list, create the following function. The function accepts 4 arguments, a pointer to the list, a pointer to the (new) node, and the nodes that will come before and after it once inserted. If the previous node is NULL, the new node becomes the head of the list. If the next node is NULL, the new node becomes the tail of the list. Node* insert (List* list, Node* node, Node* prev, Node* next) { if (!list !node) return 0; node->next = next; node->prev = prev; if (!prev) list->head = node; else prev->next = node; if (!next) list->tail = node; else next->prev = node; return node; } With this function in place, you can simplify calls to it by creating the following helper functions: Node* insert_before (List* list, Node* node, Node* next) { if (!next) return insert (list, node, list->tail, 0); else return insert (list, mode, next->prev, next); } Node* insert_after (List* list, Node* node, Node* prev) { if (!prev) return insert (list, node, 0, list->head); else return insert (list, mode, prev, prev->next); }

What is an intrathoracic node?

An intrathoracic node is a node within the chest cavity.

How many pointers will have to be changed if a node is deleted from a linear linked list?

For a singly-linked list, only one pointer must be changed. If the node about to be deleted (let's call it node for the sake of argument) is the head of the list, then the head node pointer must be changed to node->next. Otherwise, the node that comes before the deleted node must change its next pointer to node->next. Note that given a singly-linked node has no knowledge of its previous node, we must traverse the list from the head in order to locate that particular node, unless the node is the head of the list: void remove (List* list, Node* node) { if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;} else {Node* prev = list->head;while (prev->next != node) prev = prev->next; // locate the node's previous nodeprev->next = node->next;}} Note that the remove function only removes the node from the list, it does not delete it. This allows us to restore the node to its original position, because the node itself was never modified (and thus still refers to its next node in the list). So long as we restore all removed nodes in the reverse order they were removed, we can easily restore the list. In order to delete a node completely, we simply remove it and then free it:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node);free (node);} For a doubly-linked list, either two or four pointers must be changed. If the node about to be deleted is the head node, then the head node pointer must be changed to n->next and n->next->prev must be changed to NULL, otherwise, n->prev->next becomes n->next. In addition, if the node about to be deleted is the tail node, then the tail node pointer must be changed to n->prev and n->prev->next must be changed to NULL, otherwise, n->next->prev becomes n->prev. Deletion from a doubly-linked list is generally quicker than deletion from a singly linked list because a node in a doubly-linked list knows both its previous node and its next node, so there's no need to traverse the list to locate the previous node to the one being deleted. void remove (List* list, Node* node) {if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;node->next->prev = NULL;} else {node->prev->next = node->next; }if (list->tail == node) {list->tail = node->prev;node->prev->next = NULL;} else {node->next->prev = node->prev; }} Again, to physically delete the node we simply remove and then free the node:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node); free (node); }

Insert delete operations in Doubly Linked List?

Deleting a given nodeif( ) = node.prev;if( node.prev ) =;if( head node ) tail = node.prev;delete( node );Inserting at the headif( head ) head.prev = node; = head;head = node;Inserting at the tailif( tail ) = node;node.prev = tail;tail = node;Inserting after a given nodenode.prev = given; =;if( = node; = node;Inserting before a given = given;node.prev = given.prev;if( given.prev ) = node;given.prev = node;

What is Activity-on-node?

Activity on node is a diagram where every node (circle) represents an activity.

What is Cardiopulmonary node?

cardiopulmonary node

What is the algorithm to find largest node in a binary search tree?

Since a binary search tree is ordered to start with, to find the largest node simply traverse the tree from the root, choosing only the right node (assuming right is greater and left is less) until you reach a node with no right node. You will then be at the largest node.for (node=root; node!= NULL&&node->right != NULL; node=node->right);This loop will do this. There is no body because all the work is done in the control expressions.

An algorithm to delete elements from a linked list?

Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while ( != node) { prev =; } end while // Assign the node's next node to the previous node's next node =; } end if // Before deleting the node, reset its next node = null; // Now delete the node. delete node;

What is the AV node?

The AV node is the atrio-ventricular node, which assists in regulating the heartbeat (along with the SA or sino-atrial node).

Can you insert a node at any place in linklist without traversing it?

Yes, with limitations... If you have the address of a node in the linklist, you can insert a node after that node. If you need to insert the node before that node, you need to traverse the list, unless the linklist is a doubly-linkedlist

What is a simple node?

In computer programming, a simple node is a structure that holds two pointers. The first pointer refers to the data that is indirectly associated with the node, while the other refers to the next node in the sequence. Simple nodes are typically used in forward lists (singly-linked lists) where we keep track of the head node only. The last node in the list refers to NULL as there can be no next node after the last node. We can insert new data into the list knowing only the address of the data. A new node is constructed which then refers to the data and to the current head of the list. The new node then becomes the head of the list. Insertions at the head are performed in constant time. Inserting anywhere else in the list requires that we traverse the nodes recursively, following each node's next pointer, starting from the head, stopping at the node that should come after the new node. That node then becomes the new node's next node (if the node reaches the end of the list, the next node is NULL). Since we traversed recursively, we can return the newly inserted node to the caller, which can then be assigned to the caller's next node. All other recursions simply return the node we traversed to, thus leaving the caller's next node unchanged. The following example shows a simple node implementation for an ordered list of type int: typedef struct Node_t { // a simple node int* data; Node_t* next; } Node; Node* insert (int* data, Node* node) { // insert data if (!node *node->data > *data ) { // insertion point reached (end recursions) Node* pnode = malloc (sizeof (Node)); // create a new node pnode->data = data; // attach the data pnode->next = node; // refer to the next node (may be NULL) return pnode; // return the new node so the previous node can be updated } // if we get this far, the given node comes before the new data // delegate to the next node, the return value is the new or existing next node node->next = insert (data, node->next); return node; // return the node (it remains the previous node's next node) } void print_all (Node* node) { // print the given node and all that follow it while (node) { printf ("%d ", *node->data); node = node->next; } } Node* destroy_all (Node* node) // destroy the given node and all that follow it while (node) { Node* next = node->next; // refer to the next node (may be NULL) free (node->data); // release the current node's data free (node); // release the node itself node = next; // make the next node current (may be NULL) } return node; // always NULL } int main(void) { // The test program... srand ((unsigned) time (NULL)); // seed a random number generator Node* head = NULL; // the head node of the list (initially NULL for an empty list) for (int i=0; i<10; ++i) { // insert 10 random integers int* pint = malloc (sizeof (int)); // allocate a new integer on the free store if (!pint) break; // allocation failed, stop inserting! *pint = rand () % 10; // assign a random integer value (range 0:9) head = insert (pint, head); // insert the data (the return value is the new or existing head) } print_all (head); // print all the nodes starting from the head node head = delete_all (head); // destroy all the nodes starting from the head (returns NULL) return 0; }

How do you insert a new node in a tree in c plus plus?

In order to insert a new node you must first determine where the node will be inserted. For instance, in an unbalanced binary tree (sorting tree), you will traverse from the root node, comparing its data to the data you wish to insert. If the data to be inserted is greater then you traverse to its right node, otherwise you traverse to its left node. You repeat this process for each node you traverse to until there is no node to traverse to. You then create a new node for the data and assign the current node's left or right pointer to the new node. That is, if the data is greater than the current node, and the current node's right node is NULL, the new node becomes the current node's right node. You then start at the root to insert the next node.

What is parent node?

In programming, a parent node is any node that holds some reference to a child node. The child node may itself be a parent node. A classic example of parent/child node usage is the binary tree, where every node in the tree may hold a reference to up to 2 children. Nodes that have no children are known as leaf nodes.

What node serves as a pacemaker?

sinus node

What is a node in medical terminology?

Node in medical terms most commonly refers to a lymph node.

What is a lymph node biopsy?

A lymph node biopsy is a procedure in which all or part of a lymph node is removed and examined to determine if there is cancer within the node.

Correct order of intrinsic cardiac conduction?

Its one of these, cant remember which one though: AV node, SA node AV bundle, Purkinje fibres. SA node, AV bundle, Purkinje fibres, AV node. SA node, AV node, AV bundle, Purkinje fibres. Purkinje fibres, SA node, AV node, AV bundle.

How do you you delete a node in singly linked list only pointer to that node is given in C?

Ya We can Do that actually.1. Copy the content of the next node in to the node that has to be deleted.2. Assign the next pointer of the newly copied node of to the next pointer of the node from the content has been copied.3. Delete the node from the data has copied.Another way of above problem is do a memcpy on current node from next node. and delete the next node would be more faster and optimized.

How do you insert a new node into circular linked list and where the new node will be inserted?

If the node is to be inserted in sorted order, you must traverse the list from the head node or first node to locate the insertion point. You then point the node to its next and previous nodes, either side of the insertion point. Then update those nodes to point at the new node.That is, assuming node is to be inserted between prev and next, you would use the following algorithm (assuming every node has next and prev members) = next;node.prev = prev;next.prev = node; = node;

How do you recursively reverse a singly linked list using c plus plus?

In this case recursion is not necessary, an iterative process is more efficient. Start by pointing at the head node. While this node has a next node, detach its next node and insert that node at the head. Repeat until the original head node has no next node. At that point the head has become the tail and all the nodes are completely reversed. The following example shows how this can be implemented, where the list object contains a head node (which may be NULL), and each node has a next node. The tail node's next node is always NULL. void reverse(list& lst) { if( node* p=lst.head ) { while(p->next) { node*; // point to the next node; // detach the next node; // insert the detached node at the head lst.head=n; // set the new head node } } }

Can you delete the head node from doubly linked list?

If by 'head node' you simply mean the first node, then yes; but if 'head node' means the special element which is not supposed to ever be deleted (aka sentinel node), then no.