Java does not support object overriding. It does support operator overloading by means of the "+" symbol which is used for both numeric addition as well as string concatenation.
There is no sizeOf() operator in Java.
Java does not have the sizeOf() operator or any operator that gives an equivalent result.
Java does not support opperator overloading, so the answer to your question is: none.
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
In C++, overriding and function, method, or operator is a different thing than (dynamic) polymorphism, so overriding a polymorphic method is almost entirely possible.
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An operator is a symbol that does something in Java. for ex: "+" is an arithmetic operator that adds two numbers. ">" is a logical operator that checks if one number is greater than the other. There are many different types of operators in Java like Arithmetic, Logical, Relational and Assignment operators
when overriding of a class or a method is necessary, they can be declared as abstract
"==" in java is the binary operator which compares two values and gives a boolean result While "=" in java is a assignment operator which assigns a value to a variable.
In Java, the multiplication operator is represented by the asterisk, "*". This was not invented by Java; most programming languages, as well as programs such as Excel, use the same symbol.
conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++
It refers to the currently running object.