Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
The volume of one mole of gas at Standard Temperature and Pressure (STP) is 22.4 liters.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
The volume of one mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters.
The amount of oxygen is 0,067 moles.
1mol of a gas occupies 24 dm3 at STP, so 2.2mol X 24 mol/dm3 =52.8dm3 or 5280cm3
First of all, you have to know what substance you are dealing with. Then you would have to know its density. Using the density you can convert liters to kilograms. Then you get the gram-molecular weight (using the chemical formula of this substance and the Periodic Table of Elements) and with that you can convert kilograms to moles.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
The volume is 64,8 L.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
The amount of oxygen is 0,067 moles.
liter = unit of volume mole = unit of concentration
Standard molar volume of the substance.
The volume of one mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters.
Assuming I've understood what you're trying to ask: first calculate the mass, then convert that to a volume using the density.
1 mole of gas at STP occupies 22.4 liters.
This is the molar volume of an ideal gas at a given temperature and pressure.