Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
The amount of oxygen is 0,067 moles.
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
1mol of a gas occupies 24 dm3 at STP, so 2.2mol X 24 mol/dm3 =52.8dm3 or 5280cm3
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
The volume is 64,8 L.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
The amount of oxygen is 0,067 moles.
liter = unit of volume mole = unit of concentration
Standard molar volume of the substance.
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
Assuming I've understood what you're trying to ask: first calculate the mass, then convert that to a volume using the density.
1 mole of gas at STP occupies 22.4 liters.
This is the molar volume of an ideal gas at a given temperature and pressure.